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matlab可真费劲啊
- Ek__3->SetBinContent(1,119);
- Ek__3->SetBinContent(2,33);
- Ek__3->SetBinContent(3,16);
- Ek__3->SetBinContent(4,11);
- Ek__3->SetBinContent(5,10);
- Ek__3->SetBinContent(6,4);
- Ek__3->SetBinContent(7,4476);
- Ek__3->SetBinContent(8,602);
复制代码
import re
def extract_numbers(input_string):
pattern = r'\((\d+),(\d+)\)'
matches = re.findall(pattern, input_string)
numbers = [(int(match[0]), int(match[1])) for match in matches]
return numbers
input_string = '''
Ek__3->SetBinContent(1,119);
Ek__3->SetBinContent(2,33);
Ek__3->SetBinContent(3,16);
Ek__3->SetBinContent(4,11);
Ek__3->SetBinContent(5,10);
Ek__3->SetBinContent(6,4);
Ek__3->SetBinContent(7,4476);
Ek__3->SetBinContent(8,602);
'''
numbers = extract_numbers(input_string)
for number in numbers:
print(number)
用这个吧
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