[已解决]怎么实现把两个列表联合起来统计

937135952

假设这么一个场景，name里记录每次访客名字，date里记录每位访客访问日期。每位访客多次来访只计入1，要统计每日访客人数（重复不算）

name = ["张三","李四","王五”","李四","张三","李四","王五”]
date = ["01-03","01-03","01-03","01-03","01-02","01-02","01-01"]

统计结果应该是：01-03：3人，01-02：两人，01-01：1人。
求出大佬们应该如何实现

最佳答案

月排行榜 / 总排行榜

hrpzcf

2021-10-19 23:49:32

name = ["张三", "李四", "王五", "李四", "张三", "李四", "王五"]
date = ["01-03", "01-03", "01-03", "01-03", "01-02", "01-02", "01-01"]

record = dict()
for d, n in zip(date, name):
    if d not in record:
        record[d] = [n]
    else:
        if n in record[d]:
            continue
        record[d].append(n)
for d, i in record.items():
    print("{}: {}人".format(d, len(i)))

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937135952

每位访客每日多次来访只计入1

傻眼貓咪

date = ["01-03","01-03","01-03","01-03","01-02","01-02","01-01"]

for i in range(10):
    x = f"01-0{i}"
    if x in date:
        print(f"{x}：{date.count(x)}人")

01-01：1人
01-02：2人
01-03：4人

kogawananari

name列表好像完全没用到 只用到了date列表的次数记录吗

937135952

傻眼貓咪 发表于 2021-10-19 18:52

不是的，01-03只能计3人，因为李四是当天重复来访

hrpzcf

name = ["张三", "李四", "王五", "李四", "张三", "李四", "王五"]
date = ["01-03", "01-03", "01-03", "01-03", "01-02", "01-02", "01-01"]

record = dict()
for d, n in zip(date, name):
    if d not in record:
        record[d] = [n]
    else:
        if n in record[d]:
            continue
        record[d].append(n)
for d, i in record.items():
    print("{}: {}人".format(d, len(i)))