[已解决]SLE5 课堂内容：为啥我输出的long int 占8个字节呢

ziqiyang

<#include<stdio.h>

int main()
{
    printf("int = %lu\n",sizeof(int));
    printf("short int = %d\n",sizeof(short));
    printf("long int = %d\n",sizeof(long));
    printf("long long int = %d\n",sizeof(long long));
    printf("char = %d\n",sizeof(char));
    printf("_Bool = %d\n",sizeof(_Bool));
    printf("float = %d\n",sizeof(float));
    printf("double = %d\n",sizeof(double));
    printf("long double = %d\n",sizeof(long double));
   
    return 0;
}>
输出结果是<int = 4
short int = 2
long int = 8
long long int = 8
char = 1
_Bool = 1
float = 4
double = 8
long double = 16
Program ended with exit code: 0>
带你学C带你飞第6课，跟着小甲鱼老师打的，没问题，输出确实long int占8个字节，不明白了.


顺便问下，我用的XCODE， 这个程序里所有printf语句都提示“Format specifies type 'int' but the argument has type 'unsigned long'”
求老鸟指导

最佳答案

月排行榜 / 总排行榜

claws0n

2018-9-4 17:44:39

printf("int = %lu\n",sizeof(int));  //应该是 %d

其实是要看机器与编译器的位元数，再来是看编译器。因为没有严格规定~

跳转到最佳答案楼层

BngThea

long只能保证 大于等于 int
不同机器的结果不一样

claws0n

printf("int = %lu\n",sizeof(int));  //应该是 %d

其实是要看机器与编译器的位元数，再来是看编译器。因为没有严格规定~

Krant5

你的编译器是64位的，就会这样