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#include <stdio.h>
#include <Windows.h>
void map(char(*square)[20])
{
int i, j;
for (i = 0; i < 10; i++)
{
for (j = 0; j < 20; j++)
{
printf("%c", *(*(square + i) + j));
}
printf("\n");
}
}
static void GotoXY(int x, int y)
{
COORD position = {2*x, y };
SetConsoleCursorPosition(GetStdHandle(STD_OUTPUT_HANDLE), position);
}
static void HideCursor()
{
CONSOLE_CURSOR_INFO cci;
cci.bVisible = FALSE;
cci.dwSize = sizeof(cci);
HANDLE handle = GetStdHandle(STD_OUTPUT_HANDLE);
SetConsoleCursorInfo(handle, &cci);
}
int main()
{
HideCursor();
printf("请输入大写的WASD进行操作,了解操作请按回车\n");
char square[10][20] = { "--------------------",\
"| |",\
"| |",\
"| |", \
"| |", \
"| |", \
"| |",\
"| |",\
"| |",\
"--------------------" };
map(square);
COORD pos = { 1, 1 };
getchar();
system("cls");
map(square);
GotoXY(1, 1);
puts("■");
while (1)
{
char z = getch();
system("cls");
map(square);
if (z == 'W' || 'A' || 'S' || 'D')
{
if (z == 'W')
pos.Y--;
if (z == 'A')
pos.X--;
if (z == 'S')
pos.Y++;
if (z == 'D')
pos.X++;
if (pos.X < 1)
pos.X = 1;
if (pos.Y < 1)
pos.Y = 1;
if (pos.X > 9)
pos.X = 9;
if (pos.Y > 8)
pos.Y = 8;
GotoXY(pos.X, pos.Y);
puts("■");
}
}
getchar();
return 0;
}
这个可以做到在一个框里■四处走动，但是为了保证y轴只有一个■而用了system("cls"),但这样也导致了我做的框每次都会被删除然后重新显示，所以我想问问有什么办法可以让框不消失，而■在y轴也只显示一个？
#include <stdio.h>
#include <string.h>
#include <Windows.h>
void map(char *square[])
{
for(int i = 0; square[i]; ++i)
puts(square[i]);
}
static void GotoXY(int x, int y)
{
COORD position = {x, y};
SetConsoleCursorPosition(GetStdHandle(STD_OUTPUT_HANDLE), position);
}
static void HideCursor()
{
CONSOLE_CURSOR_INFO cci;
cci.bVisible = FALSE;
cci.dwSize = sizeof(cci);
HANDLE handle = GetStdHandle(STD_OUTPUT_HANDLE);
SetConsoleCursorInfo(handle, &cci);
}
int main(void)
{
HideCursor();
printf("请输入大写的WASD进行操作,了解操作请按回车\n");
getchar();
system("cls");
char *square[] = {
"--------------------",
"| |",
"| |",
"| |",
"| |",
"| |",
"| |",
"| |",
"| |",
"--------------------",
NULL
};
const int MAP_WIDTH = 20 - 3;
const int MAP_HEIGHT = 10 - 2;
map(square);
COORD pos = {1, 1};
COORD old_pos = pos;
while(1)
{
GotoXY(old_pos.X, old_pos.Y);
puts(" ");
GotoXY(pos.X, pos.Y);
puts("■");
int ch = getch();
old_pos = pos;
switch(ch)
{
case 'W':
case 'w':
--pos.Y;
break;
case 'S':
case 's':
++pos.Y;
break;
case 'A':
case 'a':
--pos.X;
break;
case 'D':
case 'd':
++pos.X;
break;
}
if(pos.X < 1)
pos.X = 1;
if(pos.Y < 1)
pos.Y = 1;
if(pos.X > MAP_WIDTH)
pos.X = MAP_WIDTH;
if(pos.Y > MAP_HEIGHT)
pos.Y = MAP_HEIGHT;
}
return 0;
}
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狗仔卡
发表于 2018-9-25 14:36:59
置顶卡
千斤顶
显身卡
发表于 2018-9-25 15:29:51
楼主
所以如果往底层发展有哪些出路呢？