[已解决]fputs的wen't

hickttye

#include <stdio.h>
#define STLEN 14
int main(void)
{
        char words[STLEN];

        puts("Enter a string,please.");
        fgets(words, STLEN, stdin);
        printf("Your string twice (puts(), then fputs()):\n");
        puts(words);
        fputs(words, stdout);
        puts("Enter another string,please.");
        fgets(words, STLEN, stdin);
        printf("Your string twice (puts(), then fputs()):\n");
        puts(words);
        fputs(words, stdout);
       
        puts("Done.");

        getchar();
        return 0;
}
为什么第一个fputs打印完后，下一个打印会换行，
而第二个fputs打印完之后，打印“Done”就不会换行？

最佳答案

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xypmyp

2019-6-2 06:15:22

Notice that fputs not only differs from puts in that the destination stream can be specified, but also fputs does not write additional characters, while puts appends a newline character at the end automatically.

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ba21

不知道你想说什么，我看没区别

xypmyp

Notice that fputs not only differs from puts in that the destination stream can be specified, but also fputs does not write additional characters, while puts appends a newline character at the end automatically.

hickttye

ba21 发表于 2019-6-2 00:14
不知道你想说什么，我看没区别

第二个fputs书上是连接着Done的

hickttye

xypmyp 发表于 2019-6-2 06:15
Notice that fputs not only differs from puts in that the destination stream can be specified, but al ...

but the frist fputs appends a newline

hickttye

xypmyp 发表于 2019-6-2 06:15
Notice that fputs not only differs from puts in that the destination stream can be specified, but al ...

I understand