[已解决]这种改进如何改进呢~

QQ27891996

print("欢迎进行python文字的第三次文字游戏改进测试")
temp = input("please fall a number in the bank")
guess = int(temp)
while guess != 8:
    chance = 3
    chance = chance -1
    if guess >8:
        print("bigger than answer")
    else :
        print("smaller than answer")

    temp = input("please try again ")
    guess =int(temp)
print("you are right")
input("The game is over!")
while chance == 0:
    print("sorry, you have 3 times to answer this question")
input("the game is over")

最佳答案

月排行榜 / 总排行榜

冬雪雪冬

2019-6-2 19:55:21

1. print("欢迎进行python文字的第三次文字游戏改进测试")
   
2. temp = input("please fall a number in the bank")
   
3. guess = int(temp)
   
4. chance = 2
   
5. while chance != 0:
   
6.    
   
7.    
   
8.     if guess >8:
   
9.         print("bigger than answer")
   
10.     elif guess <8:
    
11.         print("smaller than answer")
    
12.     else:
    
13.         break
    
14.     temp = input("please try again ")
    
15.     guess =int(temp)
    
16.     chance = chance -1
    
17. if guess != 8:
    
18.     print("sorry, you have 3 times to answer this question")
    
19. else:
    
20.     print("you are right")
    
21. print("The game is over!")

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跳转到最佳答案楼层

QQ27891996

英语有点烂，不要介意。

QQ27891996

我想让chance = 0的时候，就结束这个游戏，
但是 好像while 一直重复的时候，会反复运行chance = 3
这就会导致一直退不出去。

冬雪雪冬

1. print("欢迎进行python文字的第三次文字游戏改进测试")
   
2. temp = input("please fall a number in the bank")
   
3. guess = int(temp)
   
4. chance = 2
   
5. while chance != 0:
   
6.    
   
7.    
   
8.     if guess >8:
   
9.         print("bigger than answer")
   
10.     elif guess <8:
    
11.         print("smaller than answer")
    
12.     else:
    
13.         break
    
14.     temp = input("please try again ")
    
15.     guess =int(temp)
    
16.     chance = chance -1
    
17. if guess != 8:
    
18.     print("sorry, you have 3 times to answer this question")
    
19. else:
    
20.     print("you are right")
    
21. print("The game is over!")

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QQ27891996

冬雪雪冬 发表于 2019-6-2 19:55

谢谢大佬，原来要先做一个while的机会语句。

迷茫的兔子

1. import random
   
2. #获取1-30的随机数quession
   
3. quession = random.randint(1,30)
   
4. #定义while循环标记
   
5. active = True
   
6. while active:
   
7.     #定义次数计数器
   
8.     for i in range(6,0, -1):
   
9.         #获取用户输入
   
10.         answer = int(input("请输入1-30的整数回答问题："))
    
11.         print('目前还有%d次猜测机会!' % i)
    
12.         if answer > quession:
    
13.             print("猜大了，请努力")
    
14.         elif answer < quession:
    
15.             print("猜小了，请努力")
    
16.         elif answer == quession:
    
17.             print("真棒，回答正确！正确答案为%d ." % quession)
    
18.             #如果用户回答正确，重置while标记退出循环
    
19.             active = False
    
20.             break
    
21.     #猜测次数用完后，判断用户是否想继续游戏        
    
22.     else:
    
23.         count = input("目前已经没有回答机会，请问是否放弃游戏[y/n]：")
    
24.         if count == "n":
    
25.             continue
    
26.         else:
    
27.             break
    
28.             
    
29. 这是我的猜数代码，有兴趣可以参考下

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