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You're given strings J representing the types of stones that are jewels, and S representing the stones you have. Each character in S is a type of stone you have. You want to know how many of the stones you have are also jewels.
The letters in J are guaranteed distinct, and all characters in J and S are letters. Letters are case sensitive, so "a" is considered a different type of stone from "A".
Example 1:
Input: J = "aA", S = "aAAbbbb"
Output: 3
Example 2:
Input: J = "z", S = "ZZ"
Output: 0
Note:
S and J will consist of letters and have length at most 50.
The characters in J are distinct.
class Solution {
public int numJewelsInStones(String J, String S) {
if(S.length() == 0) return 0;
char[] charArray = S.toCharArray();
int count = 0;
for(char i : charArray){
if(J.indexOf(i) != -1){
count++;
}
}
return count;
}
}
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