函数调用问题

wuyoujiao

各位大神，我在程序中定义了七个函数，想实现用随机函数来随机调用其中任意一个函数，如何实现？我采用的办法是把函数名保存在列表中，利用随机索引来调用函数，但是不行。

wp231957

形参都一致吗 返回类型也是一致的吗

冬雪雪冬

def fun1():
    pass

def fun2():
    pass

def fun3():
    pass

lst = [fun1, fun2, fun3]
import random
random.choice(lst)()

zltzlt

from random import choice


def fun1():
    print('fun1')


def fun2():
    print('fun2')


def fun3():
    print('fun3')


def fun4():
    print('fun4')


def fun5():
    print('fun5')


def fun6():
    print('fun6')


def fun7():
    print('fun7')


fun_list = ['fun1', 'fun2', 'fun3', 'fun4', 'fun5', 'fun6', 'fun7']


def fun():
    # 随机调用一个函数
    exec(choice(fun_list) + "()")


fun()

wuyoujiao

list=['image_I','image_L','image_J','image_O','image_S','image_T','image_Z']
list[random.randint(0,6)]+'()'
这种方式也是可以的啦？

wp231957

wuyoujiao 发表于 2019-12-17 08:13
list=['image_I','image_L','image_J','image_O','image_S','image_T','image_Z']
list[random.randint(0, ...

import random
    
def  image_I():
   print('image_I')
   
def  image_L():
   print('image_l')
   
def  image_J():
   print('image_j')   

def  image_O():
   print('image_o')

def  image_S():
   print('image_s')

def  image_T():
   print('image_t')

def  image_Z():
   print('image_z')   
   
lst=['image_I','image_L','image_J','image_O','image_S','image_T','image_Z']
eval(random.choice(lst)+'()')
eval(lst[random.randint(0,6)]+'()')

'''
e:\pytest>python ex23.py
image_t
image_s

e:\pytest>python ex23.py
image_z
image_l

e:\pytest>python ex23.py
image_o
image_t

e:\pytest>python ex23.py
image_j
image_z

e:\pytest>python ex23.py
image_o
image_z

'''

wuyoujiao

看了各位的回复，查找了资料，才知道还有evel和exec 这样的好东西。谢谢

啄眷鸟

阿巴阿巴，其实我觉得设置一个随机数然后不同数字为条件设分支语句也可以？我真的是大新手