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- import time
- class Record:
- def __init__(self, initval=None, name=None):
- self.val = initval
- self.name = name
- self.filename = "record.txt"
- def __get__(self, instance, owner):
- with open(self.filename, 'a', encoding='utf-8') as f:
- f.write("%s 变量于北京时间 %s 被读取,%s = %s\n" % \
- (self.name, time.ctime(), self.name, str(self.val)))
- return self.val
- def __set__(self, instance, value):
- filename = "%s_record.txt" % self.name #这里定义filemname的作用
- with open(self.filename, 'a', encoding='utf-8') as f:
- f.write("%s 变量于北京时间 %s 被修改, %s = %s\n" % \
- (self.name, time.ctime(), self.name, str(value)))
- self.val = value
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问题:__set__中再次定义filename的作用?
__set__中文件写入调用的文件名self.filename应当还是一开始定义的‘record.txt’吧,然后以‘a’的方式在最后继续写入。这样filename的定义就没有用了啊
hm...这题我刚做完,感觉是没什么用,理论上应该是在一个record.txt里完成多个变量的记录工作,不存在多个变量分多个文件的情况。
之前没注意答案,一对比才发现我是个直接贴路径的粗人。。。
- import time as t
- import os
- class Record:
- def __init__(self, value, name):
- self.value = value
- self.name = name
-
- def __get__(self, instance, owner):
- with open("E:\\Python_homework\\46\\record.txt", 'a') as f:
- f.writelines("Variable %s was read at %s, %s = %s \n" %(self.name, t.asctime(), self.name, self.value))
- return self.value
- def __set__(self, instance, value):
- self.value = value
- with open("E:\\Python_homework\\46\\record.txt", 'a') as f:
- f.writelines("Variable %s was modified at %s, %s = %s \n" %(self.name, t.asctime(), self.name, self.value))
- def __delete__(self, instance):
- del self.value
- class Test:
- x = Record(10, 'x')
- y = Record(8.8, 'y')
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