[已解决]求检查代码

小诺爷

mima1 = r'''`!@#$%^&*()_+-=/*{}[]\|'";:/?,.<>'''
mima2 = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'
mima3 = '0123456789'
shuru = input("请输入需要判断的密码组合：")
changdu = len(shuru)

while (shuru.isspace() or changdu == 0):
    shuru = input("空白字符无效请重新输入：")
    changdu = len(shuru)

if changdu <=8 :
    changdu_len = 1
elif 8 < changdu < 16 :
    changdu_len = 2
else:
    changdu_len = 3

anquan = 3

for temp in shuru:
    if temp in mima1:
        anquan += 1
        break
for temp in shuru:
    if temp in mima2:
        anquan += 1
        break
for temp in shuru:
    if temp in mima3:
        anquan += 1
        break

while 1:
    print("您输入得密码评级为：",end= " ")
    if anquan == 1 or changdu == 1:
        print("低")
    elif anquan == 3 and changdu == 3 and (shuru[0]in mima2):
        print("高")
    else:
        print("中")
    break
这个代码怎么总是显示密码是中  我哪里出错了  求大佬检查一下

最佳答案

月排行榜 / 总排行榜

Twilight6

2020-6-5 08:18:46

[b]因为你中间的代码给 anquan = 3 赋值了 3  你应该赋值 0 后面才能判断   如果你赋值 3 后面 if 条件应该是判断 anquan = 4   或  anquan = 6

还有 下面if 条件 应该是判断长度的 changdu_len 而不是 changdu

你这边条件 ：shuru[0]in mima2 意思是开头密码要字母吗? 可以删了

完整代码：

mima1 = r'''`!@#$%^&*()_+-=/*{}[]\|'";:/?,.<>'''
mima2 = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'
mima3 = '0123456789'
shuru = input("请输入需要判断的密码组合：")
changdu = len(shuru)

while (shuru.isspace() or changdu == 0):
    shuru = input("空白字符无效请重新输入：")
    changdu = len(shuru)

if changdu <=8 :
    changdu_len = 1
elif 8 < changdu < 16 :
    changdu_len = 2
else:
    changdu_len = 3

anquan = 0

for temp in shuru:
    if temp in mima1:
        anquan += 1
        break
for temp in shuru:
    if temp in mima2:
        anquan += 1
        break
for temp in shuru:
    if temp in mima3:
        anquan += 1
        break
while 1:
    print("您输入得密码评级为：",end= " ")
    if anquan == 1 or changdu_len == 1:
        print("低")
    elif anquan == 3 and changdu_len == 3 :
        print("高")
    else:
        print("中")
    break

[/b]

跳转到最佳答案楼层

xiaosi4081

你那个else可能要给条件

Twilight6

[b]因为你中间的代码给 anquan = 3 赋值了 3  你应该赋值 0 后面才能判断   如果你赋值 3 后面 if 条件应该是判断 anquan = 4   或  anquan = 6

还有 下面if 条件 应该是判断长度的 changdu_len 而不是 changdu

你这边条件 ：shuru[0]in mima2 意思是开头密码要字母吗? 可以删了

完整代码：

mima1 = r'''`!@#$%^&*()_+-=/*{}[]\|'";:/?,.<>'''
mima2 = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'
mima3 = '0123456789'
shuru = input("请输入需要判断的密码组合：")
changdu = len(shuru)

while (shuru.isspace() or changdu == 0):
    shuru = input("空白字符无效请重新输入：")
    changdu = len(shuru)

if changdu <=8 :
    changdu_len = 1
elif 8 < changdu < 16 :
    changdu_len = 2
else:
    changdu_len = 3

anquan = 0

for temp in shuru:
    if temp in mima1:
        anquan += 1
        break
for temp in shuru:
    if temp in mima2:
        anquan += 1
        break
for temp in shuru:
    if temp in mima3:
        anquan += 1
        break
while 1:
    print("您输入得密码评级为：",end= " ")
    if anquan == 1 or changdu_len == 1:
        print("低")
    elif anquan == 3 and changdu_len == 3 :
        print("高")
    else:
        print("中")
    break

[/b]