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- Given a 2D binary matrix filled with 0's and 1's, find the largest rectangle containing only 1's and return its area.
- Example:
- Input:
- [
- ["1","0","1","0","0"],
- ["1","0","1","1","1"],
- ["1","1","1","1","1"],
- ["1","0","0","1","0"]
- ]
- Output: 6
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- class Solution:
- def maximalRectangle(self, matrix: List[List[str]]) -> int:
- if matrix == None or len(matrix) == 0 or len(matrix[0]) == 0:
- return 0
- m = len(matrix)
- n = len(matrix[0])
- height = [0] * n
- res = 0
- for row in matrix:
- for i in range(n):
- height[i] = height[i] + 1 if row[i] == '1' else 0
- stack = []
- for i in range(n + 1):
- if i == n:
- curt = -1
- else:
- curt = height[i]
- while stack and curt <= height[stack[-1]]:
- h = height[stack.pop()]
- if len(stack) == 0:
- w = i
- else:
- w = i - stack[-1] - 1
- res = max(res, h * w)
- stack.append(i)
- return res
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