[已解决]python第37课 课后习题 动动手0

张图南

在类当中的函数能不能调用另一个函数，如果可以，应该怎么做？
我的代码问题出在哪？
class Ticket_price:
    def adult(self,days):
        if 1 <= days <= 5:
            return 100
        else:   
            return 120
    def children(self,days):
        return 0.5 * adult(self,days)

…………………………运行结果…………………………
a = Ticket_price()
>>> a.children(5)
Traceback (most recent call last):
  File "<pyshell#11>", line 1, in <module>
    a.children(5)
  File "D:/PYTHON/python小程序/037-0.py", line 8, in children
    return 0.5*adult(self,days)
NameError: name 'adult' is not defined

最佳答案

月排行榜 / 总排行榜

zltzlt

2020-8-9 15:40:33

张图南 发表于 2020-8-9 15:37
不对啊，还是会报错
a.children()
Traceback (most recent call last):

这样呢？

class Ticket_price:
    def adult(self,days):
        if 1 <= days <= 5:
            return 100
        else:   
            return 120
    def children(self,days):
        return 0.5 * self.adult(days)

跳转到最佳答案楼层

zltzlt

这样做：

class Ticket_price:
    def adult(self,days):
        if 1 <= days <= 5:
            return 100
        else:   
            return 120
    def children(self,days):
        return 0.5 * self.adult(self,days)

张图南

zltzlt 发表于 2020-8-9 15:30
这样做：

不对啊，还是会报错
a.children()
Traceback (most recent call last):
  File "<pyshell#16>", line 1, in <module>
    a.children()
TypeError: children() missing 1 required positional argument: 'days'
>>> a.children(4)
Traceback (most recent call last):
  File "<pyshell#17>", line 1, in <module>
    a.children(4)
  File "D:/PYTHON/python小程序/037-0.py", line 8, in children
    return 0.5 * self.adult(self,days)
TypeError: adult() takes 2 positional arguments but 3 were given

zltzlt

张图南 发表于 2020-8-9 15:37
不对啊，还是会报错
a.children()
Traceback (most recent call last):

这样呢？

class Ticket_price:
    def adult(self,days):
        if 1 <= days <= 5:
            return 100
        else:   
            return 120
    def children(self,days):
        return 0.5 * self.adult(days)