[已解决]绘制图表报错

曲速飞跃

错误：

Traceback (most recent call last):
  File "D:\my.code\CityMorning Tools\TurtleTomato\TurtleTomato.py", line 157, in <module>
    plt.pie(sizes,   autopct='%1.1f%%',
  File "C:\Users\Charlie\AppData\Local\Programs\Python\Python38\lib\site-packages\matplotlib\pyplot.py", line 2810, in pie
    return gca().pie(
  File "C:\Users\Charlie\AppData\Local\Programs\Python\Python38\lib\site-packages\matplotlib\__init__.py", line 1431, in inner
    return func(ax, *map(sanitize_sequence, args), **kwargs)
  File "C:\Users\Charlie\AppData\Local\Programs\Python\Python38\lib\site-packages\matplotlib\axes\_axes.py", line 2995, in pie
    x = np.asarray(x, np.float32)
  File "C:\Users\Charlie\AppData\Local\Programs\Python\Python38\lib\site-packages\numpy\core\_asarray.py", line 83, in asarray
    return array(a, dtype, copy=False, order=order)
ValueError: could not convert string to float: '1,1,2'

代码：

import matplotlib.pyplot as plt
        sizes = [s]
        plt.pie(sizes,   autopct='%1.1f%%',
        shadow=True, startangle=90)
        plt.axis('equal') 
        plt.show()

s = '1,1,2'

最佳答案

月排行榜 / 总排行榜

Twilight6

2020-8-16 14:02:52

改成这样，你字符串不能直接拿去用，切割逗号然后转为 int 即可

import matplotlib.pyplot as plt
s = '1,1,2'
sizes = [ int(i) for i in s.split(',')]
plt.pie(sizes,   autopct='%1.1f%%',
shadow=True, startangle=90)
plt.axis('equal')
plt.show()

跳转到最佳答案楼层

Twilight6

改成这样，你字符串不能直接拿去用，切割逗号然后转为 int 即可

import matplotlib.pyplot as plt
s = '1,1,2'
sizes = [ int(i) for i in s.split(',')]
plt.pie(sizes,   autopct='%1.1f%%',
shadow=True, startangle=90)
plt.axis('equal')
plt.show()

txxcat

如果一定要用变量s，直接把列表赋值给s就可以了。

import matplotlib.pyplot as plt
sizes = s
plt.pie(sizes,   autopct='%1.1f%%',
shadow=True, startangle=90)
plt.axis('equal') 
plt.show()

s=[1,1,2]