请问如何生成时间列表？

cdkeycdma · 发表于 2020-9-6 10:58:12

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用range（1，10）可以成生1-10之间的数字，请问如何生成9：00-10：00之间的分钟，比如[9：00,9:01,9:02]

疾风怪盗 · 发表于 2020-9-6 11:15:26

import pandas as pd
data=pd.date_range(start='09:01',end='09:30',freq='min')
print(data)

DatetimeIndex(['2020-09-06 09:01:00', '2020-09-06 09:02:00',
            '2020-09-06 09:03:00', '2020-09-06 09:04:00',
            '2020-09-06 09:05:00', '2020-09-06 09:06:00',
            '2020-09-06 09:07:00', '2020-09-06 09:08:00',
            '2020-09-06 09:09:00', '2020-09-06 09:10:00',
            '2020-09-06 09:11:00', '2020-09-06 09:12:00',
            '2020-09-06 09:13:00', '2020-09-06 09:14:00',
            '2020-09-06 09:15:00', '2020-09-06 09:16:00',
            '2020-09-06 09:17:00', '2020-09-06 09:18:00',
            '2020-09-06 09:19:00', '2020-09-06 09:20:00',
            '2020-09-06 09:21:00', '2020-09-06 09:22:00',
            '2020-09-06 09:23:00', '2020-09-06 09:24:00',
            '2020-09-06 09:25:00', '2020-09-06 09:26:00',
            '2020-09-06 09:27:00', '2020-09-06 09:28:00',
            '2020-09-06 09:29:00', '2020-09-06 09:30:00'],
            dtype='datetime64[ns]', freq='T')

kogawananari · 发表于 2020-9-6 12:55:11

import time

start = '2020-08-30 09:50:00'
end = '2020-08-30 10:00:00'

start_timestamp = time.mktime(time.strptime(start,"%Y-%m-%d %H:%M:%S"))
end_timestamp = time.mktime(time.strptime(end,"%Y-%m-%d %H:%M:%S"))

a = map(lambda x:time.strftime("%Y-%m-%d %H:%M:%S",time.localtime(x)),range(int(start_timestamp),int(end_timestamp),60))
print(list(a))

#['2020-08-30 09:50:00', '2020-08-30 09:51:00', '2020-08-30 09:52:00', '2020-08-30 09:53:00', '2020-08-30 09:54:00', '2020-08-30 09:55:00', '2020-08-30 09:56:00', '2020-08-30 09:57:00', '2020-08-30 09:58:00', '2020-08-30 09:59:00']

Cool_Breeze · 发表于 2020-9-6 13:32:24

本帖最后由 Cool_Breeze 于 2020-9-6 19:15 编辑

 for i in range(100):
        print('{:02}:{:02}'.format(9 + i // 60, i%60))

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