为啥我的二次命名不管用呢？

望舒朝晖

想让用pop 删除的表示出来
这个three 跟four 怎么有毛病啊


names=['zhanglinxia','chenmeiqi','wuyan']
one_names=names.pop(1)
two_names=names.insert(2,'yuyang')

print(names[0].title()+",nice to meet you!")
print(names[1].title()+",nice to meet you!")
print(names[2].title()+",nice to meet you!")
print("sorry,I can only visit one guests!")

three_names=names.pop(2)
four_names=names.pop(1)

print('sorry,I can't visit '+three_names.title())
print('sorry,I can't visit '+four_names.tilte())
print(names[0].title()+',nice to meet you!')



File "<ipython-input-15-d579e0eea14a>", line 13
    print('sorry,I can't visit '+three_names.title())
                       ^
SyntaxError: invalid syntax



显示结果有问题，哪里错了呢？

LuLD

print('sorry,I can't visit '+three_names.title()) 因为 这个单引号，导致后面成了非法字符
can ' t，中间的那个单引号 与 sorry前的单引号 成了一对儿

一定要用的话  换成双引号  或者 加上转义符 \
print(”sorry,I can't visit“+three_names.title())


还有 print('sorry,I can't visit '+four_names.tiltle())  four 少了 一个L

望舒朝晖

果然是这个原因，感谢！

望舒朝晖

怎么看不到最佳答案了？我想给你的答案设置一下来着，找不到哪里可以选择最佳答案了