[已解决]关于列表和循环

木水盗人

请各位大佬帮忙检查下循环那里该怎么改

1. world = input()
   
2. world01 = world.split()[0]
   
3. world02 = world.split()[1]
   
4. text = input()
   
5. t = text.split()
   
6. i = 1
   
7. final = 0
   
8. while i<=len(t):
   
9.     if t[ci] == world01:
   
10.         final=final+1
    
11.         i+=1
    
12.     elif t[i]==world02:
    
13.         final=final+1
    
14.         i+=1
    
15.     else:
    
16.         i+=1
    
17.     print(final)
    
18. 
    
19.         
    
20.         
    

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最佳答案

月排行榜 / 总排行榜

jtxs0000

2021-3-6 09:14:00

1. world = input()
   
2. world01 = world.split()[0]
   
3. world02 = world.split()[1]
   
4. text = input()
   
5. t = text.split()
   
6. 
   
7. result =  sum(1 for i in range(len(t)) if t[i] == world01 or t[i] == world02)
   
8. # 如果上面的还没有学到就用下面的
   
9. 
   
10. # result = 0
    
11. # for i in range(len(t)):
    
12. #     if t[i] == world01 or t[i] == world02:
    
13. #         result += 1
    
14. 
    
15. print(result)

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跳转到最佳答案楼层

yuedong

world = input('请输入要检测的关键字：')
world01 = world.split()[0]
world02 = world.split()[1]
text = input('请输入要检测的语句：')
t = text.split()
i = 0
final = 0
while i < len(t):
    if t[i] == world01:
        final = final + 1
        i += 1
    elif t[i] == world02:
        final = final + 1
        i += 1
    else:
        i+=1
print('关键字出现的次数是：',final)

jtxs0000

1. world = input()
   
2. world01 = world.split()[0]
   
3. world02 = world.split()[1]
   
4. text = input()
   
5. t = text.split()
   
6. 
   
7. result =  sum(1 for i in range(len(t)) if t[i] == world01 or t[i] == world02)
   
8. # 如果上面的还没有学到就用下面的
   
9. 
   
10. # result = 0
    
11. # for i in range(len(t)):
    
12. #     if t[i] == world01 or t[i] == world02:
    
13. #         result += 1
    
14. 
    
15. print(result)

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fishggg

world = input("请输入要校验的单词：")
world01 = world.split()[0]
world02 = world.split()[1]
text = input("请输入待校验的文本：")
t = text.split()
i = 1
final = 0
if (world01 not in t) and (world02 not in t):
    print(final)  #都不在里面就不要循环校验了
else:
    while i < len(t):
        final = final +1 if (t[i] == world01) or (t[i] == world02) else final
        i += 1
    print(final)