有大佬帮忙看一道题吗

py是我爹

Write a function called same_pattern that returns true or false depending on whether two stringshave the same pattern of characters. More precisely, two strings have the same pattern if they are ofthe same length and if two characters in the first string are equal, if and only if the characters in thecorresponding positions in the second string are also equal. Below are some examples of patterns thatare the same and patterns that differ (keep in mind that the method should return the same value nomatter what order the two strings are passed). 1st String 2nd String Same Pattern? --------------- -------------- ------------------  "" "" True
"a" "x" True
"a" "ab" False
"ab" "ab" True
"aa" "xy" False
"aba" "+-+" True
"---" "aba" False
"abcabc" "zodzod" True
"abcabd" "zodzoe" True
"abcabc" "xxxxxx" False
"aaassscccn" "aaabbbcccd"
True "asasasasas" "xyxyxyxyxy" True
"ascneencsa" "aeiouuoiea" True
"aaassscccn" "aaabbbcccd" True
Your function should take two parameters: the two strings to compare. You are allowed to createnew strings, but otherwise you are not allowed to construct extra data structures to solve this problem(no list, set, dictionary, etc). You are limited to the string functions on the cheat sheet.

wyksyc

因为直接打字太麻烦所以我写在了纸上
file:///C:/Users/DELL/Desktop/%E5%87%BD%E6%95%B0same_pattern.jpg

wyksyc

怎么发图片啊

wyksyc

                               
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wyksyc

好吧一开始我以为是电脑存储地址。。。

逃兵

def same_pattern(a,b):
    la,lb = len(a),len(b)
    if la == lb == 1:
        return True
    if la != lb:
        return False
    for i in range(la):
        if not a.index(a[i]) == b.index(b[i]):
            return False
            break
    else:
        return True