带参数的宏定义求助

学C的大叔

按道理打印出来COUNTS()有 0 个参数，为啥程序运行结果却是有1个参数？请高手指教

#include <stdio.h>

#define ARGUMENTS(A1, A2, A3, A4, A5, A6, A7, A8, A9, A10, A11, ...) A11
#define COUNTS(...) ARGUMENTS(FISHC, ## __VA_ARGS__, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0)

int main(void)
{
        printf("COUNTS()有 %d 个参数。\n", COUNTS());
        printf("COUNTS(1, 2, 3)有 %d 个参数\n", COUNTS(1, 2, 3));
        printf("COUNTS("Apple", "Banana", "Cat", "Dog")有 %d 个参数\n", COUNTS("Apple", "Banana", "Cat", "Dog"));

        return 0;
}

学C的大叔

谁能帮帮忙啊，谢谢

学C的大叔

救命啊，求大神帮忙解决

学C的大叔

来个大神，救救我吧