马上注册,结交更多好友,享用更多功能^_^
您需要 登录 才可以下载或查看,没有账号?立即注册
x
本帖最后由 我爱橙 于 2022-3-10 16:11 编辑
Q:设p1和p2是指向同一个字符串的指针变量,c为字符变量,则以下不能正确执行的赋值语句是
A.c=*p1+*p2; //指针不能计算
B.p2=c;
C.p1=p2;
D.c=*p1*(*p2);
BCD尝试运行程序了,但都卡在设计p1和p2是指向同一个字符串的指针变量上了QAQ
B.#include <stdio.h>
#include <math.h>
int main()
{
char *p1=*p2"crazy",c;
p2=c;
printf("p1=%c\n",p1);//p1=
printf("*p1=%c\n",*p1);//*p1=
printf("p2=%c\n",p2);//p2=
printf("*p2=%c\n",*p2);//*p2=
return 0;
}
6 17
[Error] 'p2' was not declared in this scope
7 10
[Error] 'c' was not declared in this scope
C.#include <stdio.h>
#include <math.h>
int main()
{
char *p1=*p2="crazy",c;
p1=p2;
printf("p1=%c\n",p1);//p1=
printf("*p1=%c\n",*p1);//*p1=
printf("p2=%c\n",p2);//p2=
printf("*p2=%c\n",*p2);//*p2=
return 0;
}
6 17
[Error] 'p2' was not declared in this scope
D.#include <stdio.h>
#include <math.h>
int main()
{
char *p1=*p2="crazy,c;
c=*p1*(*p2);
printf("p1=%c\n",p1);//p1=
printf("*p1=%c\n",*p1);//*p1=
printf("p2=%c\n",p2);//p2=
printf("*p2=%c\n",*p2);//*p2=
return 0;
}
6 17
[Error] 'p2' was not declared in this scope
7 7
[Error] 'c' was not declared in this scope
|