NO.113 指针变量赋值

我爱橙 · 发表于 2022-3-10 16:11:51

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本帖最后由我爱橙于 2022-3-10 16:11 编辑

Q：设p1和p2是指向同一个字符串的指针变量，c为字符变量，则以下不能正确执行的赋值语句是
A.c=*p1+*p2; //指针不能计算
B.p2=c;
C.p1=p2;
D.c=*p1*(*p2);

BCD尝试运行程序了，但都卡在设计p1和p2是指向同一个字符串的指针变量上了QAQ

B.

#include <stdio.h>
#include <math.h>
int main()
{
char *p1=*p2"crazy",c;
p2=c;
printf("p1=%c\n",p1);//p1=
printf("*p1=%c\n",*p1);//*p1=
printf("p2=%c\n",p2);//p2=
printf("*p2=%c\n",*p2);//*p2=
return 0;
}

复制代码

6 17
[Error] 'p2' was not declared in this scope
7 10
[Error] 'c' was not declared in this scope

C.

#include <stdio.h>
#include <math.h>
int main()
{
char *p1=*p2="crazy",c;
p1=p2;
printf("p1=%c\n",p1);//p1=
printf("*p1=%c\n",*p1);//*p1=
printf("p2=%c\n",p2);//p2=
printf("*p2=%c\n",*p2);//*p2=
return 0;
}

复制代码

6 17
[Error] 'p2' was not declared in this scope

D.

#include <stdio.h>
#include <math.h>
int main()
{
char *p1=*p2="crazy,c;
c=*p1*(*p2);
printf("p1=%c\n",p1);//p1=
printf("*p1=%c\n",*p1);//*p1=
printf("p2=%c\n",p2);//p2=
printf("*p2=%c\n",*p2);//*p2=
return 0;
}

复制代码

6 17
[Error] 'p2' was not declared in this scope
7 7
[Error] 'c' was not declared in this scope

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