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转不过来呀!
assume cs:code
code segment
start:mov ax,cs
mov ds,ax
mov si,offset do0
mov ax,0
mov es,ax
mov di,200h
mov cx,offset do0end - offset do0
cld
rep movsb
mov ax,0
mov es,ax
mov word ptr es:[0*4],200h
mov word ptr es:[0*4+2],0
mov ax,4c00h
int 21h
do0: jmp short do0start
db 'welcome to masm!'
do0start: mov ax,cs
mov ds,ax
mov si,202h ;si为什么是202h,它的段地址是哪里?如果段地址是0,那么前两步的mov ax,cs可否改为mov ax,0
mov ax,0b800h
mov es,ax
mov di,12*160+2*36
mov cx,16
s: mov al,[si]
mov es:[di],al
inc si
add di,2
loop s
mov ax,4c00h
int 21h
do0end: nop
code ends
end start
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