[已解决]怎么统计这个文件中出现频率排前10的整数。（代码）

yangbaowen

生成一个大文件data.txt,要求1200行，每行随即为0~20的整数。
读取data.txt文件，统计这个文件中出现频率排前10的整数。

最佳答案

月排行榜 / 总排行榜

isdkz

2022-3-20 12:41:11

from operator import itemgetter
import random

# 生成文件
with open('data.txt', 'w') as fp:
    lst = (str(random.randint(0,20))+'\n' for _ in range(1200))
    fp.writelines(lst)

# 统计文件
with open('data.txt') as fp:
    result = {}
    for line in fp:
        temp = int(line[:-1])
        result[temp] = result.get(temp, 0) + 1
    result = dict(sorted(result.items(), key=itemgetter(1,0), reverse=True))
    for k, v in tuple(result.items())[:10]:
        print(f'随机数：{k}, 出现次数：{v}')

跳转到最佳答案楼层

ckblt

# 写入

import random


with open("data.txt", "w", encoding="utf-8") as f:
    s = ""
    for i in range(1, 1201):
        s += str(random.randint(0, 20)) + "\n"
    
    f.write(s[:-1])


# 读取

d = dict([(i, 0) for i in range(0, 21)])

with open("data.txt", "r", encoding="utf-8") as f:
    n = f.read().split("\n")
    for i in n:
        d[int(i)] += 1

result = [i[0] for i in sorted(d.items(), reverse=True, key=lambda d: d[1])][:10]

for i in result:
    print(i)

isdkz

from operator import itemgetter
import random

# 生成文件
with open('data.txt', 'w') as fp:
    lst = (str(random.randint(0,20))+'\n' for _ in range(1200))
    fp.writelines(lst)

# 统计文件
with open('data.txt') as fp:
    result = {}
    for line in fp:
        temp = int(line[:-1])
        result[temp] = result.get(temp, 0) + 1
    result = dict(sorted(result.items(), key=itemgetter(1,0), reverse=True))
    for k, v in tuple(result.items())[:10]:
        print(f'随机数：{k}, 出现次数：{v}')

yangbaowen

isdkz 发表于 2022-3-20 12:41

大佬

yangbaowen

ckblt 发表于 2022-3-20 12:38