[已解决]如何使用BeautifulSoup提取说有href后面的网址

redaiconglin · 发表于 2022-4-15 17:22:53

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from bs4 import BeautifulSoup

html_doc = """
<html>
<head>
<title>关联获取演示</title>
<meta charset="utf-8"/>
</head>
<body>
<p class="p-1" value = "1"><a href="https://item.jd.com/12353915.html">零基础学Python</a></p>
第一个p节点下文本
<div class="div-1" value = "2"><a href="https://item.jd.com/12451724.html">Python从入门到项目实践</a></div>
<p class="p-3" value = "3"><a href="https://item.jd.com/12512461.html">Python项目开发案例集锦</a></p>
<div class="div-2" value = "4"><a href="https://item.jd.com/12550531.html">Python编程锦囊</a></div>
</body>
</html>
"""

soup = BeautifulSoup(html_doc, features="lxml")
print() 如何使用Beautifulsoup才能提取所有href后面的网址谢谢老师够帮我解答谢谢了

最佳答案

月排行榜 / 总排行榜

isdkz

2022-4-15 17:33:59

from bs4 import BeautifulSoup

html_doc = """

<html>

<head>

<title>关联获取演示</title>

<meta charset="utf-8"/>

</head>

<body>

<p class="p-1" value = "1"><a href="https://item.jd.com/12353915.html">零基础学Python</a></p>

第一个p节点下文本

<div class="div-1" value = "2"><a href="https://item.jd.com/12451724.html">Python从入门到项目实践</a></div>

<p class="p-3" value = "3"><a href="https://item.jd.com/12512461.html">Python项目开发案例集锦</a></p>

<div class="div-2" value = "4"><a href="https://item.jd.com/12550531.html">Python编程锦囊</a></div>

</body>

</html>

"""

soup = BeautifulSoup(html_doc, features="lxml")

urls = [i['href'] for i in soup.find_all('a')] # 注意这行

print(urls)
复制代码

跳转到最佳答案楼层

isdkz · 发表于 2022-4-15 17:33:59

from bs4 import BeautifulSoup

html_doc = """

<html>

<head>

<title>关联获取演示</title>

<meta charset="utf-8"/>

</head>

<body>

<p class="p-1" value = "1"><a href="https://item.jd.com/12353915.html">零基础学Python</a></p>

第一个p节点下文本

<div class="div-1" value = "2"><a href="https://item.jd.com/12451724.html">Python从入门到项目实践</a></div>

<p class="p-3" value = "3"><a href="https://item.jd.com/12512461.html">Python项目开发案例集锦</a></p>

<div class="div-2" value = "4"><a href="https://item.jd.com/12550531.html">Python编程锦囊</a></div>

</body>

</html>

"""

soup = BeautifulSoup(html_doc, features="lxml")

urls = [i['href'] for i in soup.find_all('a')] # 注意这行

print(urls)
复制代码

redaiconglin · 发表于 2022-4-15 18:08:27

isdkz 发表于 2022-4-15 17:33

谢谢老师

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[已解决]如何使用BeautifulSoup提取说有href后面的网址

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