[已解决]哪位大佬帮忙看看怎么解决（小白一脸懵逼）

NAGAYA

警告信息：
警告        C6064        缺少“scanf_s”的整型参数(对应于转换说明符“2”)。       
警告        C4473        “scanf_s”: 没有为格式字符串传递足够的参数        Project1       

#include<stdio.h>
int main(void)
{
        long ilong;
        short ishort;
        int num1 = 1;
        int num2 = 2;
        char ichar[10] ;
        printf("Enter the long interger:\n");
        scanf_s("%ld", &ilong);
        printf("Enter the short interger:\n");
        scanf_s("%hd", &ishort);
        printf("Enter the number:\n");
        scanf_s("%d*%d", &num1, &num2);
        printf("Enter the string but only show three character\n");
        scanf_s("%3s", ichar);

        printf("the long interger is %ld\n", ilong);
        printf("the short interger is %hd\n", ishort);
        printf("the num1 is :%d\n", num1);
        printf("the num2 is :%d\n", num2);
        printf("the three character are :%s\n", ichar);

        return 0;
}

最佳答案

月排行榜 / 总排行榜

傻眼貓咪

2022-7-4 21:27:11

#include<stdio.h>
int main(void)
{
    long ilong;
    short ishort;
    int num1 = 1;
    int num2 = 2;
    char ichar[10];
    printf("Enter the long interger:\n");
    scanf_s("%ld", &ilong);
    printf("Enter the short interger:\n");
    scanf_s("%hd", &ishort);
    printf("Enter the number:\n");
    scanf_s("%d*%d", &num1, &num2);
    printf("Enter the string but only show three character\n");
    scanf_s("%3s", ichar, 10); // <---------------------------------- 注意这里

    printf("the long interger is %ld\n", ilong);
    printf("the short interger is %hd\n", ishort);
    printf("the num1 is :%d\n", num1);
    printf("the num2 is :%d\n", num2);
    printf("the three character are :%s\n", ichar);

    return 0;
}

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wp231957

scanf_s并不通用，除了微软的visual stdio 系列
其他的编译器好像都不认

NAGAYA

wp231957 发表于 2022-7-4 21:21
scanf_s并不通用，除了微软的visual stdio 系列
其他的编译器好像都不认

我用的就是vs2022,听说scanf函数改了，之前的编程书上的代码运行起来总会出错

傻眼貓咪

#include<stdio.h>
int main(void)
{
    long ilong;
    short ishort;
    int num1 = 1;
    int num2 = 2;
    char ichar[10];
    printf("Enter the long interger:\n");
    scanf_s("%ld", &ilong);
    printf("Enter the short interger:\n");
    scanf_s("%hd", &ishort);
    printf("Enter the number:\n");
    scanf_s("%d*%d", &num1, &num2);
    printf("Enter the string but only show three character\n");
    scanf_s("%3s", ichar, 10); // <---------------------------------- 注意这里

    printf("the long interger is %ld\n", ilong);
    printf("the short interger is %hd\n", ishort);
    printf("the num1 is :%d\n", num1);
    printf("the num2 is :%d\n", num2);
    printf("the three character are :%s\n", ichar);

    return 0;
}

wp231957

NAGAYA 发表于 2022-7-4 21:23
我用的就是vs2022,听说scanf函数改了，之前的编程书上的代码运行起来总会出错

还有一个参数，是写入数据的长度

柿子饼同学

可以用 gets() 和 puts() 函数

NAGAYA

傻眼貓咪 发表于 2022-7-4 21:27

谢谢大佬，还有就是第十四行那里这样写的话时只能输入一个数吗？我想输入两个的时候程序好像就终止了。