函数-Ⅶ_lambda表达式

BrightXiong

>>> def squareX(x):
...         return x * x
...
>>> squareX(3)
9
>>> squareY = lambda y : y * y
>>> squareY(3)
9
>>> # 传统定义的函数，函数名就是一个函数的引用：
>>> squareX
<function squareX at 0x01997778>
>>> # 而 lambda 表达式，整个表达式就是一个函数的引用：
>>> squareY
<function <lambda> at 0x01AAA340>
>>> y = [lambda x : x * x, 2, 3]
>>> y
[<function <lambda> at 0x01AAA2F8>, 2, 3]
>>> y[0](y[1])
4
>>> print(y)
[<function <lambda> at 0x01AAA2F8>, 2, 3]
>>> y[0](y[2])
9
>>> list(filter(lambda x : x % 2, range(10)))
[1, 3, 5, 7, 9]

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