python

pan11

该咋样才能让hint在第四次猜测后出现，就是不管前面人放弃与否，都会在第四次出现






#introduce the game and rules briefly
print("Three games, each game guess a number between 1 and 12.")
print("The game will end if you guess the right number or you run out of turns, each game you can guess 3 times.")
#Have each player enter their name
player1 = input("Enter the name of the two players: ")
player2 = input("Enter the name of the other player: ")
win1 = 0
win2 = 0
hint = True
#play 3 games total
for i in range (3):
    #pick a random number between 1 and 12
    import random
    correct_num = random.randint(1,12)
    print(correct_num)
   
    guess = []
    count = 1
   
    guessed_number = []
    while guess != correct_num and count <= 6:
        #take turns to guess the number
        if count % 2 == 0:
            player = player1
        else:
            player = player2
        if count > 1:
            print("You have already guessed: ",guessed_number)
        guess = float(input(player+" guess a number between 1 and 12: "))
        guessed_number.append(guess)
      
        
        
        
        #if one player win,the game ends
        if guess == correct_num:
            print(player,"congratulations, you are right!")
            
            if player == player1:
                win1 = win1 + 1
            else:
                win2 = win2 + 1
        #tell them if the guess is bigger or smaller               
        else:

            if guess > correct_num:
                print(player,"your number is bigger.")
            else:
                print(player,"your number is smaller.")
            #give the hint
               
            if hint == True and count>=4 and guess != correct_num :
                if correct_num % 2 == 0:
                    print("Hint: the correct number is even")
                else:
                    print("Hint: the correct number is odd")  
                hint = False   
            #let one player give up part way through the game            
            if count < 7:
                if player == player1:
                    Y = input(player2 + " Do you want to give up? [y/n]")
                else:
                    Y = input(player1 + " Do you want to give up? [y/n]")
                if Y == "n":
                    count = count + 1
                elif Y == "y":
                    count = count + 2   

        #if no winner, tell them they are losers   
        if count >= 6 and guess != correct_num and hint == False:
            print(player1,"and",player2,"you are all losers.")
            count = count + 6
    if i <= 1 :
        print("Now the next game begin! ")

# add an extra congratulations to the player who wins the most games
if win1 > win2:
    print(player1,"congratulations! you win the most games!")
elif win1 < win2:
    print(player2,"congratulations! you win the most games!")

        

isdkz

要让提示在第四次猜测后出现，可以将  hint  的初始值设为  False ，并在每次循环开始前将其重置为  True 。然后在判断是否需要提示的条件中加入  count == 4  的判断，即可在第四次猜测时出现提示。

修改后的代码如下：

#introduce the game and rules briefly
print("Three games, each game guess a number between 1 and 12.")
print("The game will end if you guess the right number or you run out of turns, each game you can guess 3 times.")
#Have each player enter their name
player1 = input("Enter the name of the two players: ")
player2 = input("Enter the name of the other player: ")
win1 = 0
win2 = 0
hint = False  # 修改初始值
#play 3 games total
for i in range (3):
    #pick a random number between 1 and 12
    import random
    correct_num = random.randint(1,12)
    print(correct_num)
    
    guess = []
    count = 1
    
    guessed_number = []
    while guess != correct_num and count <= 6:
        #take turns to guess the number 
        if count % 2 == 0:
            player = player1
        else:
            player = player2
        if count > 1:
            print("You have already guessed: ",guessed_number)
        guess = float(input(player+" guess a number between 1 and 12: "))
        guessed_number.append(guess)
        
        
        
        
        #if one player win,the game ends
        if guess == correct_num:
            print(player,"congratulations, you are right!")
            
            if player == player1:
                win1 = win1 + 1
            else:
                win2 = win2 + 1
        #tell them if the guess is bigger or smaller             
        else:

            if guess > correct_num:
                print(player,"your number is bigger.")
            else:
                print(player,"your number is smaller.")
            #give the hint
            
            if hint == True and guess != correct_num :
                if correct_num % 2 == 0:
                    print("Hint: the correct number is even")
                else:
                    print("Hint: the correct number is odd")  
            elif count == 4:  # 添加判断
                hint = True
            else:
                hint = False  
            
            #let one player give up part way through the game              
            if count < 7:
                if player == player1:
                    Y = input(player2 + " Do you want to give up? [y/n]")
                else:
                    Y = input(player1 + " Do you want to give up? [y/n]")
                if Y == "n":
                    count = count + 1
                elif Y == "y":
                    count = count + 2    

        #if no winner, tell them they are losers           
        if count >= 6 and guess != correct_num and hint == False:
            print(player1,"and",player2,"you are all losers.")
            count = count + 6 
    if i <= 1 :
        print("Now the next game begin! ") 

# add an extra congratulations to the player who wins the most games
if win1 > win2:
    print(player1,"congratulations! you win the most games!")
elif win1 < win2:
    print(player2,"congratulations! you win the most games!")

Mike_python小

如何在第四次猜测后出现hint？

要在第四次猜测后出现提示，你可以在代码中添加一个计数器来跟踪猜测的次数。当计数器达到4时，即第四次猜测时，你可以将hint变量设置为True，这样就会在这一轮猜测后显示提示。

下面是修改后的代码：

# introduce the game and rules brieflyprint("Three games, each game guess a number between 1 and 12.")print("The game will end if you guess the right number or you run out of turns, each game you can guess 3 times.")# Have each player enter their nameplayer1 = input("Enter the name of the two players: ")player2 = input("Enter the name of the other player: ")win1 = 0win2 = 0hint = False  # 初始化hint为False# play 3 games totalfor i in range(3):    # pick a random number between 1 and 12    import random    correct_num = random.randint(1, 12)    print(correct_num)    guess = []    count = 1    guessed_number = []    while guess != correct_num and count <= 6:        # take turns to guess the number        if count % 2 == 0:            player = player1        else:            player = player2        if count > 1:            print("You have already guessed: ", guessed_number)        guess = float(input(player + " guess a number between 1 and 12: "))        guessed_number.append(guess)        # if one player win, the game ends        if guess == correct_num:            print(player, "congratulations, you are right!")            if player == player1:                win1 = win1 + 1            else:                win2 = win2 + 1        # tell them if the guess is bigger or smaller        else:            if guess > correct_num:                print(player, "your number is bigger.")            else:                print(player, "your number is smaller.")        # give the hint        if hint == True and count >= 4 and guess != correct_num:            if correct_num % 2 == 0:                print("Hint: the correct number is even")            else:                print("Hint: the correct number is odd")        # let one player give up part way through the game        if count < 7:            if player == player1:                Y = input(player2 + " Do you want to give up? [y/n]")            else:                Y = input(player1 + " Do you want to give up? [y/n]")            if Y == "n":                count = count + 1            elif Y == "y":                count = count + 2        # if no winner, tell them they are losers        if count >= 6 and guess != correct_num and hint == False:            print(player1, "and", player2, "you are all losers.")            count = count + 6        if count == 4 and guess != correct_num:            hint = True  # 在第四次猜测后将hint设置为True    if i <= 1:        print("Now the next game begin! ")# add an extra congratulations to the player who wins the most gamesif win1 > win2:    print(player1, "congratulations! you win the most games!")elif win1 < win2:    print(player2, "congratulations! you win the most games!")

现在，当进入第四次猜测时，无论前面的玩家是否放弃，提示都会显示在屏幕上。

球一个最佳答案谢谢啦！这对我非常重要！