[已解决]求助一下

yangzhixiaohuli

6-1 计算两个复数之积
分数 10
作者 张泳
单位 浙大城市学院
本题要求实现一个计算复数之积的简单函数。

函数接口定义：
struct complex multiply(struct complex x, struct complex y);
其中struct complex是复数结构体，其定义如下：

struct complex{
    int real;
    int imag;
};
裁判测试程序样例：
#include <stdio.h>

struct complex{
    int real;
    int imag;
};

struct complex multiply(struct complex x, struct complex y);

int main()
{
    struct complex product, x, y;

    scanf("%d%d%d%d", &x.real, &x.imag, &y.real, &y.imag);
    product = multiply(x, y);
    printf("(%d+%di) * (%d+%di) = %d + %di\n",
            x.real, x.imag, y.real, y.imag, product.real, product.imag);
   
    return 0;
}

/* 你的代码将被嵌在这里 */
输入样例：
3 4 5 6
输出样例：
(3+4i) * (5+6i) = -9 + 38i

这个函数怎么写

最佳答案

月排行榜 / 总排行榜

isdkz

2023-11-11 14:27:45

#include <stdio.h>

struct complex{
    int real;
    int imag;
};

struct complex multiply(struct complex x, struct complex y);

int main()
{
    struct complex product, x, y;

    scanf("%d%d%d%d", &x.real, &x.imag, &y.real, &y.imag);
    product = multiply(x, y);
    printf("(%d+%di) * (%d+%di) = %d + %di\n", 
           x.real, x.imag, y.real, y.imag, product.real, product.imag);
    
    return 0;
}

struct complex multiply(struct complex x, struct complex y) {
    struct complex result;
    result.real = x.real * y.real - x.imag * y.imag;
    result.imag = x.real * y.imag + x.imag * y.real;
    return result;
}

跳转到最佳答案楼层

isdkz

#include <stdio.h>

struct complex{
    int real;
    int imag;
};

struct complex multiply(struct complex x, struct complex y);

int main()
{
    struct complex product, x, y;

    scanf("%d%d%d%d", &x.real, &x.imag, &y.real, &y.imag);
    product = multiply(x, y);
    printf("(%d+%di) * (%d+%di) = %d + %di\n", 
           x.real, x.imag, y.real, y.imag, product.real, product.imag);
    
    return 0;
}

struct complex multiply(struct complex x, struct complex y) {
    struct complex result;
    result.real = x.real * y.real - x.imag * y.imag;
    result.imag = x.real * y.imag + x.imag * y.real;
    return result;
}