[已解决]求求啦！！！！！！！！！！！！！！！！！！！！！

METALARISING

from tkinter import *

r = Tk()

def c():
    fileName = filedialog.askopenfilename()
    print(fileName)

Button(r, text='open_file', command=c).pack()

mainloop()
代码是这个，但是报错了。。。。。。
Exception in Tkinter callback
Traceback (most recent call last):
  File "C:\Users\Administrator\AppData\Local\Programs\Python\Python311-32\Lib\tkinter\__init__.py", line 1948, in __call__
    return self.func(*args)
           ^^^^^^^^^^^^^^^^
  File "C:\Users\Administrator\Desktop\open file.py", line 6, in c
    fileName = filedialog.askopenfilename()
               ^^^^^^^^^^
NameError: name 'filedialog' is not defined

@fishGPT

最佳答案

月排行榜 / 总排行榜

liuhongrun2022

2024-1-17 19:27:53

前面加上：from tkinter import filedialog

跳转到最佳答案楼层

FishC

嗨！看起来你遇到了一个`NameError: name 'filedialog' is not defined`的错误。这是因为你在代码中使用了`filedialog`，但是没有导入对应的模块。

要解决这个问题，你需要在代码中加上以下一行：

from tkinter import filedialog

这样就可以正常使用`filedialog`模块来打开文件对话框了。修改后的代码如下：

from tkinter import *
from tkinter import filedialog

r = Tk()

def c():
    fileName = filedialog.askopenfilename()
    print(fileName)

Button(r, text='open_file', command=c).pack()

mainloop()

希望这可以解决你的问题！如果还有其他问题，请随时问我。

以上回复来自 FishC AI 小助理，如未能正确解答您的问题，请继续追问。

liuhongrun2022

前面加上：from tkinter import filedialog

METALARISING

liuhongrun2022 发表于 2024-1-17 19:27
前面加上：from tkinter import filedialog

谢谢!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!