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实验7,终于出来了,小小的纠结了一下,学到了不少东西,高手进来指点交流一下吧,小弟第一次发讨论贴,望大家不要拍砖啊
assume cs:codesg,ds:data,ss:table
data segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15257,17800
data ends
table segment
db 21 dup ('year summ ne ??')
table ends
codesg segment
start: mov ax,data
mov ds,ax
mov ax,table
mov ss,ax
mov bp,0 ;关于这句,在debug的时候竟然没有指令,从mov ss,ax直接跳到mov si,0了
mov si,0
mov di,0
mov cx,21
mov bx,0
s: mov dx,cx
mov cx,4
s1:
mov al,[di] ;复制年份进table
mov [bp+si],al
mov al,84[di] ;复制收入进table
mov 5[bp+si],al
add di,1
add si,1
loop s1
mov al,32 ;制造空格列
mov 4[bp],al
mov 9[bp],al
mov 12[bp],al
mov 15[bp],al
mov ax,168[bx] ;复制雇员数进table
mov 10[bp],ax
add bx,2
add bp,10h ;跳到下一列
mov si,0
mov cx,dx ;取出原来存储的cx值
loop s
mov bx,0 ;初始化下一个循环
mov si,0 ;嘿嘿这个mov si,0不能掉啊,搞了一步步调试了半天才发现这里错了
mov bp,0
mov cx,21
s0:mov dx,84[bx+si+2] ;用div命令计算人均收入并存入table
mov ax,84[bx+si]
div WORD ptr 168[bx]
mov 13[bp],ax
add bx,2
add si,2
add bp,10h
loop s0
mov ax,4c00h
int 21h
codesg ends
end start
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