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就是向结构体中添加多个数据,把部分代码复制一遍出现刷屏的情况求解,具体是这样的。
以下是原来的代码:#include <stdio.h>
#include <malloc.h>
#include <stdlib.h>
#define LEN sizeof(struct student) // student结构的大小
struct student *creat(); //创建链表
struct student *del(struct student *head, int num); //del函数用于删除结点, *head即链表
//的头指针, num是要删除的结点num。
struct student *insert(struct student *head, struct student *stu_2); // 第一个参数需要被插入的链表
// 第二个参数待插入的结构的地址
void print(struct student *head); //打印链表
struct student
{
int num;
float score;
struct student *next;
};
int n; //全局变量,用来记录存放了多少数据。
void main()
{
struct student *stu, *p, stu_2;
int n;
stu = creat();
p = stu;
print( p );
printf("\nPlease input the num to delete: ");
scanf("%d", &n);
print( del(p, n) );
printf("\nPlease input the num to insert: ");
scanf("%d", &stu_2.num);
printf("Please input the score: ");
scanf("%f", &stu_2.score);
p = insert(stu, &stu_2);
print( p );
printf("\n\n");
system("pause");
}
struct student *creat()
{
struct student *head;
struct student *p1, *p2;
p1 = p2 = (struct student *)malloc(LEN); // LEN是student结构的大小
printf("Please enter the num :");
scanf("%d", &p1->num);
printf("Please enter the score :");
scanf("%f", &p1->score);
head = NULL;
n = 0;
while( p1->num )
{
n++;
if( 1 == n )
{
head = p1;
}
else
{
p2->next = p1;
}
p2 = p1;
p1 = (struct student *)malloc(LEN);
printf("\nPlease enter the num :");
scanf("%d", &p1->num);
printf("Please enter the score :");
scanf("%f", &p1->score);
}
p2->next = NULL;
return head;
}
void print(struct student *head)
{
struct student *p;
printf("\nThere are %d records!\n\n", n);
p = head;
if( head )
{
do
{
printf("学号为 %d 的成绩是: %f\n", p->num, p->score);
p = p->next;
}while( p );
}
}
struct student *del( struct student *head, int num)
{
struct student *p1, *p2;
if( NULL == head )
{
printf("\nThis list is null!\n");
goto end;
}
p1 = head;
while( p1->num != num && p1->next != NULL)
{
p2 = p1;
p1 = p1->next;
}
if( num == p1->num )
{
if( p1 == head )
{
head = p1->next;
}
else
{
p2->next = p1->next;
}
printf("Delete No: %d succeed!\n", num);
n = n-1;
}
else
{
printf("%d not been found!\n", num);
}
end:
return head;
}
struct student *insert(struct student *head, struct student *stu_2)
{
struct student *p0, *p1, *p2;
p1 = head;
p0 = stu_2;
if( NULL == head )
{
head = p0;
p0->next = NULL;
}
else
{
while( (p0->num > p1->num) && (p1->next != NULL) ) //两种情况推出while,一:
{
p2 = p1;
p1 = p1->next;
}
if( p0->num <= p1->num )
{
if( head == p1 ) // p1是头结点,插入头部
{
head = p0;
}
else // 普通情况,插入中间
{
p2->next = p0;
}
p0->next = p1;
}
else // p0的num最大,插入到末尾
{
p1->next = p0;
p0->next = NULL;
}
}
n = n+1; // 由于插入了,所以增加了一位数据成员进入链表中。
return head;
}
希望输入两个数据,将37到43行代码复制粘贴一遍,运行时输入完会出现刷屏(不知道各位能否理解我的意思),我尝试把复制的代码中的stu_2改为stu_3(当然前面定义声明一个),就解决了,不知是为什么,难道它不能被反复赋值? |