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输入两个链表a和b,要求将a中num与b中相同的结点删去。输入输出函数都测试过了,没有问题。应该是del函数的问题,每次运行都无法终止。谁能帮我看一下是为什么吗?
#include <stdio.h>
#include <malloc.h>
#define LEN sizeof(struct student)
struct student
{
int num;
int score;
struct student *next;
};
int n;
struct student *creat()//创建链表
{
struct student *head;
struct student *p1,*p2;
n=0;
p1=p2=(struct student *)malloc(LEN);
scanf("%d,%d",&p1->num,&p1->score);
head=NULL;
while(p1->num!=0)
{
n++;
if(n==1) head=p1;
else p2->next=p1;
p2=p1;
p1=(struct student *)malloc(LEN);
scanf("%d,%d",&p1->num,&p1->score);
}
p2->next=NULL;
return head;
}
void print(struct student *head)//输出函数
{
struct student *p;
p=head;
if(head!=NULL)
{
while(p!=NULL)
{
printf("%-6d%5d\n",p->num,p->score);
p=p->next;
}
}
}
struct student *del(struct student *a,struct student *b)
{
struct student *p1,*p2,*p3;
p1=a;
p2=a;
p3=b;
while(p3->num!=0)
{
while(p1->next!=NULL && p3->num!=p1->num)
{
p1=p1->next;
p2=p1;
}
if(p3->num==p1->num)//若找到p3->num,则不指向b链表的下一地址,在删节过的a链表中再寻找一次
{
if(p1==a) a=p1->next;//若p1指向的是首地址,则把第二个结点地址赋予a
else p2->next=p1->next;//否则将下一结点地址赋予前一结点地址
}
else p3=p3->next;//若未找到P3->num则指向b链表的下一地址
p1=a;
p2=a;
}
return a;
}
void main()
{
struct student *a,*b;
printf("input LL a here:\n");
a=creat();
printf("input LL b here:\n");
b=creat();
printf("LL a:\n");
print(a);
printf("LL b:\n");
print(b);
a=del(a,b);
printf("the deleted LL a:\n");
print(a);
} |
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