|

楼主 |
发表于 2018-12-27 11:57:22
|
显示全部楼层
- import easygui as g
- import os
- def show_result(start_dir):
- lines = 0
- total = 0
- text = ""
- for i in source_list:
- lines = source_list[i]
- total += lines
- text += "【%s】源文件 %d 个,源代码 %d 行\n" % (i, file_list[i], lines)
- title = '统计结果'
- msg = '您目前共累积编写了 %d 行代码,完成进度:%.2f %%\n离 10 万行代码还差 %d 行,请继续努力!' % (total, total/1000, 100000-total)
- g.textbox(msg, title, text)
-
- def calc_code(file_name):
- lines = 0
- with open(file_name) as f:
- print('正在分析文件:%s ...' % file_name)
- try:
- for each_line in f:
- lines += 1
- except UnicodeDecodeError:
- pass
- return lines
- def search_file(start_dir) :
- os.chdir(start_dir)
- for each_file in os.listdir(os.curdir) :
- ext = os.path.splitext(each_file)[1]
- if ext in target :
- lines = calc_code(each_file)
- try:
- file_list[ext] += 1
- except KeyError:
- file_list[ext] = 1
- try:
- source_list[ext] += lines
- except KeyError:
- source_list[ext] = lines
- if os.path.isdir(each_file) :
- search_file(each_file) # 递归调用
- os.chdir(os.pardir) # 递归调用后切记返回上一层目录
-
- target = ['.c', '.cpp', '.py', '.cc', '.java', '.pas', '.asm']
- file_list = {}
- source_list = {}
- g.msgbox("请打开您存放所有代码的文件夹......", "统计代码量")
- path = g.diropenbox("请选择您的代码库:")
- search_file(path)
- show_result(path)
复制代码
这是源码
你是说如果都是.py的文件,如果格式不兼容的话,就是进到except里了吧?
可是我查找的那个文件夹放的都是我的python作业,里面都是.py的文件,如果不兼容应该显示代码数量为0吧?
|
|