As you have seen from applyingArray.prototype.map(), or simplymap()earlier, themapmethod returns an array of the same length as the one it was called on. It also doesn't alter the original array, as long as its callback function doesn't. 换句话说,map是一个纯函 ...
#includestdio.h #includemath.h int main() { long long int num; float i; int n ; for (num = 100000; num 1000000; num++) { i = sqrt(num); if (i - (int)i != 0) continue; n = num / 100000;//十万位 n = (num ...
#includestdio.h int main() { int i ;//乘数 int a; scanf_s("%d", a);//输入、 int j;//第几项阶乘,m为和 long long sum,m; sum = 0; for (j=1; j = a; j++) { m = 1; for(i=1;i=j;i++) { m = i * m; ...
includestdio.h #define NUM 10//利用宏定义,代替下面的数字,以后若要更改,工作量更小 int main() { int s ; int i, sum = 0; for (i = 0; i 10; i++) { printf("请输入第%i位同学的成绩:",i + 1);//%i新东西 scanf_s("%d", s ); sum += s ; } ...