Project Euler 6 Sum square difference by python

python6

Sum square difference

The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385


The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025


Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

python code:

sum(range(1,101))**2-sum([j**2 for j in range(1,101)])

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