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本帖最后由 许楠 于 2012-1-6 12:01 编辑
还未看小甲鱼老师的视频,自己摸索写2段代码,一会儿看看小甲鱼老师怎么做的
第一段代码是第12,13,14行每行取中 显示那三行字
- assume cs:codesg
- data segment
- db 'welcome to masm!'
- data ends
- codesg segment
- start:
- mov ax,data
- mov ds,ax
- mov bx,0
- mov ax,0B800h
- mov es,ax
- mov di,720h
- mov cx,16
- s:
- mov al,byte ptr ds:[bx]
- mov ah,00000010b
- mov word ptr es:[di],ax
- inc bx
- add di,2
- loop s
- mov di,7c0h
- mov cx,16
- mov bx,0
- s1:
- mov al,byte ptr ds:[bx]
- mov ah,00100100b
- mov word ptr es:[di],ax
- inc bx
- add di,2
- loop s1
- mov di,860h
- mov cx,16
- mov bx,0
- s2:
- mov al,byte ptr ds:[bx]
- mov ah,01110001b
- mov word ptr es:[di],ax
- inc bx
- add di,2
- loop s2
- mov ax,4c00h
- int 21h
- codesg ends
- end start
复制代码
第二段代码是以第13行取中,横向依次显示那3行字,用了栈,AX本来也应该放栈里的,可是脑袋绕不过来了
- assume cs:codesg
- data segment
- db 'welcome to masm!'
- data ends
- stack segment
- dw 8 dup (0)
- stack ends
- codesg segment
- start:
- mov ax,data
- mov ds,ax
- mov bx,0
- mov ax,0B800h
- mov es,ax
- mov ax,stack
- mov ss,ax
- mov sp,8
- mov di,7a0h ;16个字=32字节,3个字段就是96个字节,每行160字节,取中是80字节,
- mov cx,3 ;96取中是48字节,80-48=32个字节,每屏25行,中间是13行,13行首偏移地址为780
- mov dl,0 ;所以780h+32h=7a0
- mov dh,01110001b
- push dx
- mov dh,00100100b
- push dx
- mov dh,00000010b
- push dx
- pop dx
- s:
- mov bp,cx ;栈被用了,用BP存CX吧
- mov cx,16
- s1:
- mov ah,dh
- mov al,byte ptr ds:[bx]
- mov word ptr es:[di],ax
- inc bx
- add di,2
- loop s1
- pop dx
- mov bx,0
- mov cx,bp
- loop s
- mov ax,4c00h
- int 21h
- codesg ends
- end start
复制代码
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