[已解决]添加列表的问题~~~

海月清辉

1. a = [1,2,3,["b","c","d"],4,5]
   
2. e = ["x","y","z","f"]

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我想把e插入到  c d之间~~~
各位大神 这个是怎么操作的啊？

1. a = [1,2,3,["b","c","d"],4,5]
   
2. e =["x","y","z","f"]
   
3. g = a[3:4]
   
4. 
   
5. print(g)
   
6. a.insert(g,e)

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报错了  而且也没法考虑索引值的问题

最佳答案

月排行榜 / 总排行榜

jackz007

2019-11-9 23:46:44

1. a = [1,2,3,["b","c","d"],4,5]
   
2. e =["x","y","z","f"]
   
3. a[3] . insert(2 , e)
   
4. print(a)

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     效果：

1. >>> a = [1,2,3,["b","c","d"],4,5]
   
2. >>> e =["x","y","z","f"]
   
3. >>> a[3] . insert(2 , e)
   
4. >>> a
   
5. [1, 2, 3, ['b', 'c', ['x', 'y', 'z', 'f'], 'd'], 4, 5]
   
6. >>>

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跳转到最佳答案楼层

jackz007

1. a = [1,2,3,["b","c","d"],4,5]
   
2. e =["x","y","z","f"]
   
3. a[3] . insert(2 , e)
   
4. print(a)

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     效果：

1. >>> a = [1,2,3,["b","c","d"],4,5]
   
2. >>> e =["x","y","z","f"]
   
3. >>> a[3] . insert(2 , e)
   
4. >>> a
   
5. [1, 2, 3, ['b', 'c', ['x', 'y', 'z', 'f'], 'd'], 4, 5]
   
6. >>>

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海月清辉

jackz007 发表于 2019-11-9 23:46
效果：

insert(2,e)   这里是从第三开始但是不包括第三是吧？

jackz007

海月清辉 发表于 2019-11-10 00:11
insert(2,e)   这里是从第三开始但是不包括第三是吧？

     插入到索引为 2 的元素的前面。

雾溟潇湘

我知道的办法是先把原位置的列表删掉，然后新建个符合要求的列表

zltzlt

正确代码：

1. a = [1,2,3,["b","c","d"],4,5]
   
2. e = ["x","y","z","f"]
   
3. g = a[3]
   
4. 
   
5. print(g)
   
6. g.insert(2, e)
   
7. print(a)

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输出：

1. ['b', 'c', 'd']
   
2. [1, 2, 3, ['b', 'c', ['x', 'y', 'z', 'f'], 'd'], 4, 5]

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海月清辉

zltzlt 发表于 2019-11-10 07:55
正确代码：

大神 你和上面的是同一个级别~~~