[已解决]用dictionary 来用七段显示器显示数字

hnldyxx551

在程序里面已经写好这个了。
seven_segment = {'0': {'a','c','d','e','b','f'},
'1': {'c','b'},
'2': {'a','d','e','b','g'},
'3': {'a','c','d','b','g'},
'4': {'g','c','f','b'},
'5': {'a','c','d','g','f'},
'6': {'a','c','d','e','g','f'},
'7': {'a','c','b'},
'8': {'a','c','d','e','b','g','f'},
'9': {'a','c','d','b','g','f'}}

我现在需要的是在我输入
>>> character(seven_segment, 'abged')
'2'
输入
>>> character(seven_segment, 'abcdeg')
False

我不知道怎么用if else来解决求大家帮忙

最佳答案

月排行榜 / 总排行榜

冬雪雪冬

2020-3-14 20:59:42

def character(seven_segment, string):
    for n, s in seven_segment.items():
        if set(string) == s:
            return n
    return False

跳转到最佳答案楼层

冬雪雪冬

def character(seven_segment, string):
    for n, s in seven_segment.items():
        if set(string) == s:
            return n
    return False