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要求描述:根据vector构建二叉树
例如 1 2 3 4 5 6 7 得到:图1
- #include <iostream>
- #include <vector>
- #include <string>
- #include<malloc.h>
- #include <math.h>
- using namespace std;
- struct TreeNode{
- int val;
- TreeNode* left;
- TreeNode* right;
- TreeNode(int x): val(x), left(NULL), right(NULL){
- }
- };
- TreeNode* CreateTree(vector<int>& input){
- TreeNode* tree = (TreeNode*)malloc(sizeof(TreeNode)*input.size());
- for(int i = 0; i < input.size() ;i++){
- tree[i].val = input[i];
- tree[i].left = NULL;
- tree[i].right = NULL;
-
- }
- for(int i = 0; i <= input.size()/2-1; i++){
- if(2*i+1 <= input.size()){
- tree[i].left = &tree[2*i+1];
- }
- if(2*i+2<=input.size()){
- tree[i].right = &tree[2*i+2];
- }
- }
- return tree;
- }
- void middle(TreeNode* root, vector<vector<int> >& res, int left, int right, int depth){
- if(root == NULL) return;
- int insert = left + (right - left) / 2;
- res[depth][insert] = root->val;
-
- middle(root->left, res, left, insert - 1, depth + 1);
- middle(root->right, res, insert + 1, right, depth + 1);
- }
- int treeDepth(TreeNode* root){
- if(root == NULL) return 0;
- return max(treeDepth(root->left) + 1, treeDepth(root->right) + 1);
- }
-
- vector<vector<int> > printTree(TreeNode* root) {
- int depth = treeDepth(root);
- int width = pow(2, depth) - 1;
- vector<vector<int> > res(depth, vector<int>(width, 0));
- middle(root, res, 0, width - 1, 0);
- return res;
- }
- int main(void){
- vector<int>input;
- int number;
- cout << "please send numbers for this tree:" << endl;
- while(cin >> number){
- input.push_back(number);
- }
- TreeNode* root = CreateTree(input);
- vector<vector<int> > res = printTree(root);
- for(int i = 0; i < res.size(); i++){
- for(int j = 0; j < res[i].size();j++){
- if(res[i][j] == 0){
- cout << " ";
- }
- else{
- cout << res[i][j];
- }
-
- }
- cout << endl;
- }
- return 0;
- }
复制代码
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-
图1
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