Python 获取可迭代对象的最后 n 个值

zltzlt

1. >>> from collections import deque
   
2. >>> n = 3
   
3. >>> print(list(deque(range(10), n)))    # 取最后 3 个值
   
4. [7, 8, 9]
   
5. >>> n = 5
   
6. >>> print(list(deque(range(10), n)))    # 取最后 5 个值
   
7. [5, 6, 7, 8, 9]

复制代码

qiuyouzhi

这样也行，就是改成 list 类型开销有点大

1. >>> a = range(10)
   
2. >>> n = 3
   
3. >>> list(a)[len(a) - n:]
   
4. [7, 8, 9]
   
5. >>> n = 5
   
6. >>> list(a)[len(a) - n:]
   
7. [5, 6, 7, 8, 9]

复制代码