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Python 爬取B站视频链接&标题
先放源码:
- from requests import get
- from lxml import etree
- def open_url(url):
- headers = {
- 'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/81.0.4044.122 Safari/537.36'
- }
- res = get(url, headers = headers)
- return res
- def get_Video(res):
- html = etree.HTML(res.text)
- name = html.xpath('//*[@class="video-item matrix"]/a/@title')
- href = html.xpath('//*[@class="video-item matrix"]/a/@href')
- for i in range(len(href)):
- href[i]='https:' + href[i]
- return name, href
-
- def main():
- keyw = input("请输入关键字:")
- url = 'https://search.bilibili.com/all?keyword=%s&from_source=nav_search&spm_id_from=333.851.b_696e7465726e6174696f6e616c486561646572.15' % keyw
- res = open_url(url)
- name, href = get_Video(res)
- temp = {} # 这个temp用于改进,可以删掉
- for i in range(len(name)):
- print(name[i], ':', href[i])
- temp[i+1] = name[i], href[i]
- if __name__ == "__main__":
- main()
复制代码
用bs4可谓极其简单,但是我想练练XPath
感觉XPath好简单,把路径关系写进去就好了。 |
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