本帖最后由 (^3^)我来啦! 于 2012-4-29 08:34 编辑
谢谢了啊!代码如下:
assume cs:codesg, ss:stack
data segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995' ;以上是表示21年的21个字符串
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
;以上表示的是21年的总收入dword数据
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15257,17800
;以上表示的是21年的员工word数据
data ends
stack segment
db 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
stack ends
table segment
db 21 dup ('year summ ne ?? ')
table ends
codesg segment
start: mov ax,table
mov ds,ax
mov bx,0
mov ax,data
mov es,ax
mov ax,stack
mov ss,ax
mov sp,16
mov di,0
mov cx,21
s: push cx
mov si,0
mov cx,4
s1: mov al,es:[bx+di];年份
mov [bx+si],al
inc si
inc di
loop s1
inc si
mov cx,4
push di
mov di,0
s2: mov al,es:54H[bx+di] ;收入
mov [bx+si],al
inc si
inc di
loop s2
pop di
inc si
mov cx,2
push di
mov di,0
s3: mov al,es:0A8H[bx+di] ;雇员
mov [bx+si],al
inc si
inc di
loop s3
pop di
add bx,10H
pop cx
loop s
mov bx,0
mov cx,21
s4: mov dx,[bx+7]
mov ax,[bx+5]
div word ptr [bx+0AH]
mov [bx+0DH],ax
add bx,10H
loop s4
mov ax,4c00H
int 21H
codesg ends
end start
谢谢各位好心人了啊!如有错误希望指正 小弟新手
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