[已解决]求助 怎么改 谢谢！

MIQIWEI

get_pair_of_largest_numbers（numbers），该函数将数字列表作为参数，并返回具有最大和的相邻数字对作为元组。您可以假定列表不为空（至少两个或更多元素），并且每个元素都是有效数字。

1. def get_pair_of_largest_numbers(numbers):
   
2.     result = [numbers[index] + numbers[index+1] for index in range(len(numbers)-1)]
   
3.     max_value = result[0]
   
4.     for index in range(len(result)):
   
5.         if result[index] > max_value:
   
6.             max_value = result[index]
   
7.     return max_value

复制代码

Test        Result
print(get_pair_of_largest_numbers([10.5, -3, -1, 11]))
(-1, 11)
print(get_pair_of_largest_numbers([ 10, 20, 3, 31, 8, 42]))
(8, 42)
print(get_pair_of_largest_numbers([ 10.5, -3]))
(10.5, -3)

最佳答案

月排行榜 / 总排行榜

Twilight6

2020-8-16 17:28:29

1. def get_pair_of_largest_numbers(numbers):
   
2.     result = [numbers[index] + numbers[index+1] for index in range(len(numbers)-1)]
   
3.     max_value = result.index(max(result))
   
4.     return tuple(numbers[max_value:max_value+2])
   
5. 
   
6. print(get_pair_of_largest_numbers([10.5, -3, -1, 11]))
   
7. print(get_pair_of_largest_numbers([ 10, 20, 3, 31, 8, 42]))
   
8. print(get_pair_of_largest_numbers([ 10.5, -3]))

复制代码

跳转到最佳答案楼层

Twilight6

1. def get_pair_of_largest_numbers(numbers):
   
2.     result = [numbers[index] + numbers[index+1] for index in range(len(numbers)-1)]
   
3.     max_value = result.index(max(result))
   
4.     return tuple(numbers[max_value:max_value+2])
   
5. 
   
6. print(get_pair_of_largest_numbers([10.5, -3, -1, 11]))
   
7. print(get_pair_of_largest_numbers([ 10, 20, 3, 31, 8, 42]))
   
8. print(get_pair_of_largest_numbers([ 10.5, -3]))

复制代码