[已解决]如何计算列表的百分比

jtxs0000

一个列表,里面有很多重复值,如何计算里面重复值的百分比并合并起来

谢谢大佬

x = [111,222,333,444,555,666,111,333,444,222,555,222,111,444]

最佳答案

月排行榜 / 总排行榜

Twilight6

2020-8-18 10:40:29

x = [111,222,333,444,555,666,111,333,444,222,555,222,111,444]
result = []
for i in set(x):
    result.append((i,'{:.2f}%'.format((x.count(i)/len(x))*100)))
print(*result)

输出结果：

(555, '14.29%') (333, '14.29%') (111, '21.43%') (666, '7.14%') (444, '21.43%') (222, '21.43%')

跳转到最佳答案楼层

qiuyouzhi

sum(set(x))

tttxiaoz

list有个count方法  可以统计某一个元素的值

x.count(111)

jtxs0000

tttxiaoz 发表于 2020-8-18 10:39
list有个count方法  可以统计某一个元素的值

要百分比

Twilight6

x = [111,222,333,444,555,666,111,333,444,222,555,222,111,444]
result = []
for i in set(x):
    result.append((i,'{:.2f}%'.format((x.count(i)/len(x))*100)))
print(*result)

输出结果：

(555, '14.29%') (333, '14.29%') (111, '21.43%') (666, '7.14%') (444, '21.43%') (222, '21.43%')

jtxs0000

qiuyouzhi 发表于 2020-8-18 10:37

比如,1个111在列表占10%,那么3个就占30%,同理,222,333这些站多少,我是想算这个,方法不限,可以应用库

jtxs0000

Twilight6 发表于 2020-8-18 10:40
输出结果：

你是这个

jtxs0000

Twilight6 发表于 2020-8-18 10:40
输出结果：

大佬,再问个问题,如果里面有中文或者英文有影响吗

永恒的蓝色梦想

jtxs0000 发表于 2020-8-18 10:45
大佬,再问个问题,如果里面有中文或者英文有影响吗

没有影响。

永恒的蓝色梦想

Twilight6 发表于 2020-8-18 10:40
输出结果：

from collections import Counter


x = [111,222,333,444,555,666,111,333,444,222,555,222,111,444]
result = []
for i, j in Counter(x).items():
    result.append((i,'{:.2f}%'.format((j/len(x))*100)))
print(*result)

效率会更好

_2_

我来试试：

x = [111,222,333,444,555,666,111,333,444,222,555,222,111,444]
def func(x: list) -> list: return [(i, j) for i in list(set(x)) for j in [_ / __ for _ in [x.count(_i) for _i in list(set(x)))] for __ in [len(x)] * len(x)]]
func(x)

没测试，可能有错

jtxs0000

谢谢各位大佬解答,只能按时间先后给最佳了,不好意思

fall_bernana

from collections import Counter
list(map(lambda k:(k[0],k[1]/len(x)),Counter(x).items()))

输出结果：

[(111, 0.21428571428571427), (222, 0.21428571428571427), (333, 0.14285714285714285), (444, 0.21428571428571427), (555, 0.14285714285714285), (666, 0.07142857142857142)]