[已解决]列表推导还原问题

159328404

将下列代码还原
>>> list1 = [(x, y) for x in range(10) for y in range(10) if x%2==0 if y%2!=0]

答案：
list1 = []

for x in range(10):
    for y in range(10):
        if x%2 == 0 and y%2 != 0:
            list1.append((x,y))

哪里错了呢

最佳答案

月排行榜 / 总排行榜

疾风怪盗

2020-9-14 19:35:47

list1 = []
for x in range(10):
    for y in range(10):
        if x % 2 == 0 and y % 2 != 0:
             list1.append((x, y))
print(list1)

list2 = [(x, y) for x in range(10) for y in range(10) if x % 2 == 0 if y % 2 != 0]
print(list2)

[(0, 1), (0, 3), (0, 5), (0, 7), (0, 9), (2, 1), (2, 3), (2, 5), (2, 7), (2, 9), (4, 1), (4, 3), (4, 5), (4, 7), (4, 9), (6, 1), (6, 3), (6, 5), (6, 7), (6, 9), (8, 1), (8, 3), (8, 5), (8, 7), (8, 9)]
[(0, 1), (0, 3), (0, 5), (0, 7), (0, 9), (2, 1), (2, 3), (2, 5), (2, 7), (2, 9), (4, 1), (4, 3), (4, 5), (4, 7), (4, 9), (6, 1), (6, 3), (6, 5), (6, 7), (6, 9), (8, 1), (8, 3), (8, 5), (8, 7), (8, 9)]


都一样的

跳转到最佳答案楼层

疾风怪盗

为什么两个if之间是and?

小甲鱼的铁粉

你写的对着呢啊，我运行了，两个结果一样

疾风怪盗

list1 = []
for x in range(10):
    for y in range(10):
        if x % 2 == 0 and y % 2 != 0:
             list1.append((x, y))
print(list1)

list2 = [(x, y) for x in range(10) for y in range(10) if x % 2 == 0 if y % 2 != 0]
print(list2)

[(0, 1), (0, 3), (0, 5), (0, 7), (0, 9), (2, 1), (2, 3), (2, 5), (2, 7), (2, 9), (4, 1), (4, 3), (4, 5), (4, 7), (4, 9), (6, 1), (6, 3), (6, 5), (6, 7), (6, 9), (8, 1), (8, 3), (8, 5), (8, 7), (8, 9)]
[(0, 1), (0, 3), (0, 5), (0, 7), (0, 9), (2, 1), (2, 3), (2, 5), (2, 7), (2, 9), (4, 1), (4, 3), (4, 5), (4, 7), (4, 9), (6, 1), (6, 3), (6, 5), (6, 7), (6, 9), (8, 1), (8, 3), (8, 5), (8, 7), (8, 9)]


都一样的

heidern0612

x和y不是并列关系。

 list1 = [(x, y) for x in range(10) for y in range(10) if x%2==0 if y%2!=0]

等同于：

list1 = []
for x in range(10):
    for y in range(10):
        if x % 2 == 0:
            if y % 2 != 0:
                list1.append((x, y))

即使结果是一样的，但是内容不一样。

159328404

小甲鱼的铁粉 发表于 2020-9-14 19:34
你写的对着呢啊，我运行了，两个结果一样

是的，我把list1打印出来才发现是对的。。。直接F5没出结果我还以为是错了