[已解决]019作业：判断字符数量问题

159328404 · 发表于 2020-9-21 14:29:25

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本帖最后由 159328404 于 2020-9-21 14:35 编辑

QQ截图20200921142834.png

def count(*params):
count1 = 0
count2 = 0
count3 = 0
count4 = 0
length1 = len(params)
for each1 in range(length1):
length2 = params[each1]
for each2 in range(length2):
if params[each1][each2].isalpha() == 1:
count1 += 1
elif params[each1][each2].isspace() == 1:
count2 += 1
elif params[each1][each2].isdigit() == 1:
count3 += 1
else:
count4 += 1
print('第' + str(each1+1) + '个字符串有：英文字母' + count1 + '个，数字' + coun3 + '个，空格' + count2 + '个，其他字符' + count4 + '个.')
count('i love 123-+*/')

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为什么会报错啊。。。

最佳答案

fall_bernana

2020-9-21 14:36:12

def count(*params):
count1 = 0
count2 = 0
count3 = 0
count4 = 0
length1 = len(params)
for each1 in range(length1):
length2 = len(params[each1])
for each2 in range(length2):
if params[each1][each2].isalpha() == 1:
count1 += 1
elif params[each1][each2].isspace() == 1:
count2 += 1
elif params[each1][each2].isdigit() == 1:
count3 += 1
else:
count4 += 1
print('第' + str(each1) + '个字符串有：英文字母' + str(count1) + '个，数字' + str(count3) + '个，空格' + str(count2) + '个，其他字符' + str(count4) + '个.')
count('i love 123-+*/')
第0个字符串有：英文字母5个，数字3个，空格2个，其他字符4个.

复制代码

fall_bernana · 发表于 2020-9-21 14:36:12

def count(*params):
count1 = 0
count2 = 0
count3 = 0
count4 = 0
length1 = len(params)
for each1 in range(length1):
length2 = len(params[each1])
for each2 in range(length2):
if params[each1][each2].isalpha() == 1:
count1 += 1
elif params[each1][each2].isspace() == 1:
count2 += 1
elif params[each1][each2].isdigit() == 1:
count3 += 1
else:
count4 += 1
print('第' + str(each1) + '个字符串有：英文字母' + str(count1) + '个，数字' + str(count3) + '个，空格' + str(count2) + '个，其他字符' + str(count4) + '个.')
count('i love 123-+*/')
第0个字符串有：英文字母5个，数字3个，空格2个，其他字符4个.

复制代码

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