[已解决]新人求助，圆周率代码为啥会报错

小彭不会飞

# pi.py
from random import random
from math import sqrt
from time import clock
DARTS = 1200
hits = 0
clock()
for i in range(1,DARTS):
    x, y = random(), random()
    dist = sqrt(x**2 + y**2)
    if dist <= 1.0:
        hits = hits + 1
pi = 4 * (hits/DARTS)
print("Pi的值是 %s" % pi)
print("程序运行时间是 %-5.5ss" % clock())

最佳答案

月排行榜 / 总排行榜

sunrise085

2020-12-15 21:30:21

那不是错误，是警告提示，意思是说在3.3版本之后就不再使用clock函数了，使用time.perf_counter 或time.process_time 代替了

1. from random import random
   
2. from math import sqrt
   
3. import time
   
4. DARTS = 1200
   
5. hits = 0
   
6. time.perf_counter()
   
7. for i in range(1,DARTS):
   
8.     x, y = random(), random()
   
9.     dist = sqrt(x**2 + y**2)
   
10.     if dist <= 1.0:
    
11.         hits = hits + 1
    
12. pi = 4 * (hits/DARTS)
    
13. print("Pi的值是 %s" % pi)
    
14. print("程序运行时间是 %-5.5ss" % time.perf_counter())

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跳转到最佳答案楼层

sunrise085

那不是错误，是警告提示，意思是说在3.3版本之后就不再使用clock函数了，使用time.perf_counter 或time.process_time 代替了

1. from random import random
   
2. from math import sqrt
   
3. import time
   
4. DARTS = 1200
   
5. hits = 0
   
6. time.perf_counter()
   
7. for i in range(1,DARTS):
   
8.     x, y = random(), random()
   
9.     dist = sqrt(x**2 + y**2)
   
10.     if dist <= 1.0:
    
11.         hits = hits + 1
    
12. pi = 4 * (hits/DARTS)
    
13. print("Pi的值是 %s" % pi)
    
14. print("程序运行时间是 %-5.5ss" % time.perf_counter())

复制代码