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题:
我的代码:- #include <stdio.h>
- main(){
- int n,m;
- int sum1=0;
- int sum2=0;
- int percent1;
- int percent2;
- float c1,c2;
- scanf("%d",&n);
- int score[n];
- int i;
- for(int m=1;m<=n;m++){
- scanf("%d",&i);
- score[m]=i;
- }
- for(int j=1;j<=n;j++){
- if(score[j]>=60){
- sum1++;
- }
- }
- for(int a=1;a<=m;a++){
- if(score[a]>=85){
- sum2++;
- }
- }
- c1=sum1/n;
- c2=sum2/n;
- percent1=(int)c1*100;
- percent2=(int)c2*100;
- printf("%d%%\n",percent1);
- printf("%d%%\n",percent2);
-
- }
复制代码
- #include <stdio.h>
- main(){
- int n,m;
- int sum1=0;
- int sum2=0;
- int percent1;
- int percent2;
- float c1,c2;
- scanf("%d",&n);
- int score[n];
- int i;
- for(int m=0;m<n;m++){
- scanf("%d",&i);
- score[m]=i;
- }
- for(int j=0;j<n;j++){
- if(score[j]>=60){
- sum1++;
- }
- }
- for(int a=0;a<n;a++){
- if(score[a]>=85){
- sum2++;
- }
- }
- c1=1.0*sum1/n;
- c2=1.0*sum2/n;
- percent1=(int)(c1*100+0.5);
- percent2=(int)(c2*100+0.5);
- printf("%d%%\n",percent1);
- printf("%d%%\n",percent2);
-
- }
复制代码
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