[已解决]python自己写的程序出了问题

Mrtu

小甲鱼20讲课后作业的第二十题
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qKWGc
""";
a=0
b=0
c=0
d=1
length=len(str1)
for i in range(length):
    if str1=='\n':
        continue
    elif str1.isupper() and d==1:
        b=1
        c=0
        a+=1
        continue
    elif str1.islower() and a==3 and b==1:
        b=0
        target=i
        d=0
        continue
    elif str1.isupper() and d==0 :
        c+=1
        continue
    elif str1.islower() and c==3:
        print(str1[target],end='')
    a=0
    b=0
    c=0
    为什么我这样输出的全是1

最佳答案

月排行榜 / 总排行榜

大马强

2021-8-3 11:29:14

1. a = 0
   
2. b = 0
   
3. c = 0
   
4. d = 1
   
5. length = len(str1)
   
6. for i in range(length):
   
7.     # print(str1[i])
   
8.     if str1[i] == '\n':
   
9.         continue
   
10.     elif str1[i].isupper() and d == 1:  # 判断大写
    
11.         b = 1
    
12.         c = 0
    
13.         a += 1
    
14. 
    
15.         if a > 3:  # 大写超过两次以上
    
16.             a = 0
    
17.         continue
    
18. 
    
19.     elif str1[i].islower() and a == 3 and b == 1:  # 判断第一个条件即三个大写开头
    
20.         b = 0
    
21.         target = i
    
22.         d = 0
    
23.         continue
    
24.     elif str1[i].isupper() and d == 0:  # 判断第二个条件，后面接着三个大写
    
25.         # print(str1[i])
    
26.         c += 1
    
27.         if c == 3:  # 就在本次循环中判断
    
28.             if str1[i+1].islower(): #判断后面哪一位是否为小写
    
29.                 print(str1[target], end='')
    
30.                 # 将所有变量设置为满足第一条件时(前面三个大写)
    
31.                 a = 3
    
32.                 b = 1
    
33.                 c = 0
    
34.                 d = 1
    
35.             else:
    
36.                 a = 0
    
37.                 b = 0
    
38.                 c = 0
    
39.                 d = 1
    
40. 
    
41.         continue
    
42.     a = 0
    
43.     b = 0
    
44.     c = 0
    
45.     d = 1

复制代码

跳转到最佳答案楼层

深谙流年

其实你可以debug一下，一步一步走，就会看到是哪里的问题了

大马强

你代码哪里有输出?

大马强

1. str1 = '粘贴的文本'
   
2. a = 0
   
3. b = 0
   
4. c = 0
   
5. d = 1
   
6. length = len(str1)  # 5
   
7. for i in range(length):  # 0~5
   
8.     if str1[i] == '\n':
   
9.         continue
   
10.     elif str1[i].isupper() and d == 1:  # 判断大写开头的字符串 不成立
    
11.         b = 1
    
12.         c = 0
    
13.         a += 1
    
14.         continue
    
15.     elif str1[i].islower() and a == 3 and b == 1:  # 判断小写开头的字符串 不成立
    
16.         b = 0
    
17.         target = i
    
18.         d = 0
    
19.         continue
    
20.     elif str1[i].isupper() and d == 0:  # 判断大写开头的字符串 不成立
    
21.         c += 1
    
22.         continue
    
23.     elif str1[i].islower() and c == 3:  # 判断小写开头的字符串 不成立
    
24.         print(str1[target], end='')
    
25.     a = 0
    
26.     b = 0
    
27.     c = 0
    

复制代码

我尝试着注释了，都不能成立呀

Mrtu

大马强 发表于 2021-8-2 18:28
我尝试着注释了，都不能成立呀

粘贴的文本太长了我只是没打上去在20讲的课后练习里面

大马强

先大概改成在这样，目前有点事，晚点再来帮你看，就你现在的代码，我把我发现的问题说出来
第一、当你第一次找到了匹配条件的字母，此时你的第一条件就已经满足了 a 继续为 3，然后接着判断其他条件
第二、d=1
第三、str[i] //我猜你是忘写了

Mrtu

大马强 发表于 2021-8-2 20:54
先大概改成在这样，目前有点事，晚点再来帮你看，就你现在的代码，我把我发现的问题说出来
第一、当你第一 ...

好的谢谢

大马强

1. a = 0
   
2. b = 0
   
3. c = 0
   
4. d = 1
   
5. length = len(str1)
   
6. for i in range(length):
   
7.     # print(str1[i])
   
8.     if str1[i] == '\n':
   
9.         continue
   
10.     elif str1[i].isupper() and d == 1:  # 判断大写
    
11.         b = 1
    
12.         c = 0
    
13.         a += 1
    
14. 
    
15.         if a > 3:  # 大写超过两次以上
    
16.             a = 0
    
17.         continue
    
18. 
    
19.     elif str1[i].islower() and a == 3 and b == 1:  # 判断第一个条件即三个大写开头
    
20.         b = 0
    
21.         target = i
    
22.         d = 0
    
23.         continue
    
24.     elif str1[i].isupper() and d == 0:  # 判断第二个条件，后面接着三个大写
    
25.         # print(str1[i])
    
26.         c += 1
    
27.         if c == 3:  # 就在本次循环中判断
    
28.             if str1[i+1].islower(): #判断后面哪一位是否为小写
    
29.                 print(str1[target], end='')
    
30.                 # 将所有变量设置为满足第一条件时(前面三个大写)
    
31.                 a = 3
    
32.                 b = 1
    
33.                 c = 0
    
34.                 d = 1
    
35.             else:
    
36.                 a = 0
    
37.                 b = 0
    
38.                 c = 0
    
39.                 d = 1
    
40. 
    
41.         continue
    
42.     a = 0
    
43.     b = 0
    
44.     c = 0
    
45.     d = 1

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大马强

你可以看看小甲鱼里的要求

1. |如果str1[i]是大写字母：
   
2. #     |-- 如果已经出现小写字母：
   
3. #     |-- -- 统计后边的大写字母
   
4. #     |-- 如果未出现小写字母：
   
5. #     |-- -- 清空后边大写字母的统计
   
6. #     |-- -- 统计前边的大写字母
   
7. #     """
   
8. |如果前边和后边都是三个大写字母：
   
9. #     |-- 如果后边第四个字母也是大写字母（不符合条件）：
   
10. #     |-- -- 清空记录B和C，重新统计
    
11. #     |-- 如果后边仅有三个大写字母（符合所有条件）：
    
12. #     |-- -- 打印结果，并清空所有记录，进入下一轮统计
    
13. #     """

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大马强

你原来代码有这些问题
1.没有考虑到开头是三个以上大写的情况
2.输出时多了一次循环，应该要在c=3的时候直接判断是否满足其他的要求，没有的话直接重新开始统计
3.输出后，此时的就已经满足了三个大写开头的条件，接着这个条件判断即可