[已解决]列表习题

dragov

欲将4个字的桥名找出来，组成一个新的列表。

1. bridge=list(["海津大桥","广场桥","解放桥","大沽桥","赤峰桥","保定桥","直沽桥","富民桥","金刚桥","金汤桥","北安桥","狮子林桥","永乐桥","大光明侨","刘庄浮桥","国泰桥"])
   
2. bridge_4=0
   
3. for i in range (len(bridge)) :
   
4.     if bridge[i] % 4 ==0 :
   
5.         bridge_4[i].append(bridge[i])
   
6. print(bridge_4)

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最佳答案

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冬雪雪冬

2021-10-11 15:14:30

1. bridge=list(["海津大桥","广场桥","解放桥","大沽桥","赤峰桥","保定桥","直沽桥","富民桥","金刚桥","金汤桥","北安桥","狮子林桥","永乐桥","大光明侨","刘庄浮桥","国泰桥"])
   
2. bridge_4=[]
   
3. for i in range (len(bridge)) :
   
4.     if len(bridge[i]) % 4 ==0 :
   
5.         bridge_4.append(bridge[i])
   
6. print(bridge_4)

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冬雪雪冬

1. bridge=list(["海津大桥","广场桥","解放桥","大沽桥","赤峰桥","保定桥","直沽桥","富民桥","金刚桥","金汤桥","北安桥","狮子林桥","永乐桥","大光明侨","刘庄浮桥","国泰桥"])
   
2. bridge_4=[]
   
3. for i in range (len(bridge)) :
   
4.     if len(bridge[i]) % 4 ==0 :
   
5.         bridge_4.append(bridge[i])
   
6. print(bridge_4)

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冬雪雪冬

1. bridge=list(["海津大桥","广场桥","解放桥","大沽桥","赤峰桥","保定桥","直沽桥","富民桥","金刚桥","金汤桥","北安桥","狮子林桥","永乐桥","大光明侨","刘庄浮桥","国泰桥"])
   
2. bridge_4=[]
   
3. for i in bridge :
   
4.     if len(i) % 4 ==0 :
   
5.         bridge_4.append(i)
   
6. print(bridge_4)

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