用列表查字典

979229413

dict1 = {"a":1,"b":5,"c":9}
f = ["a","b","c"]
print([dict1[_] for _ in f])  #1,5,9

但如果f = ["a","b","c","g"]  

就会报错，请问有更好的用列表查询字典的方法吗？

kogawananari

list(map(lambda _:dict1.get(_),f))


dict1 = {"a":1,"b":5,"c":9}
f = ["a","b","c","g"]  
返回[1, 5, 9, None]

君无泪

方法一：
dict1 = {"a":1,"b":5,"c":9}
f = ["a","b","c","g"]

print([dict1.get(key) for key in f])  # 如果获取的不存在时会返回一个默认值 None。
# 输出结果: [1, 5, 9, None]

方法二：
dict1 = {"a":1,"b":5,"c":9}
f = ["a","b","c","g"]
b = [dict1.get(key) for key in f if dict1.get(key) != None]
print(b)
# 输出结果：[1, 5, 9]

傻眼貓咪

不清楚你想要什么，希望对你有帮助

dict1 = {"a": 1, "b": 5, "c": 9}
print(*dict1.values())

1 5 9