[已解决]用Python做一个圣诞树

蜜雪冰城

圣诞节前，不要网上摘抄的，网上摘抄的那个报错!!!

最佳答案

月排行榜 / 总排行榜

suchocolate

2021-12-19 12:26:28

找到你抄的图的代码了，我这运行没有报错：

from turtle import *
import random
import time

n = 80.0

speed("fastest")
screensize(bg='seashell')
left(90)
forward(3 * n)
color("orange", "yellow")
begin_fill()
left(126)

for i in range(5):
    forward(n / 5)
    right(144)
    forward(n / 5)
    left(72)
end_fill()
right(126)

color("dark green")
backward(n * 4.8)


def tree(d, s):
    if d <= 0: return
    forward(s)
    tree(d - 1, s * .8)
    right(120)
    tree(d - 3, s * .5)
    right(120)
    tree(d - 3, s * .5)
    right(120)
    backward(s)


tree(15, n)
backward(n / 2)

for i in range(200):
    a = 200 - 400 * random.random()
    b = 10 - 20 * random.random()
    up()
    forward(b)
    left(90)
    forward(a)
    down()
    if random.randint(0, 1) == 0:
        color('tomato')
    else:
        color('wheat')
    circle(2)
    up()
    backward(a)
    right(90)
    backward(b)
time.sleep(60)

我看你抄的代码里这里错了：

跳转到最佳答案楼层

suchocolate

贴代码，贴报错，不要贴图。

suchocolate

找到你抄的图的代码了，我这运行没有报错：

from turtle import *
import random
import time

n = 80.0

speed("fastest")
screensize(bg='seashell')
left(90)
forward(3 * n)
color("orange", "yellow")
begin_fill()
left(126)

for i in range(5):
    forward(n / 5)
    right(144)
    forward(n / 5)
    left(72)
end_fill()
right(126)

color("dark green")
backward(n * 4.8)


def tree(d, s):
    if d <= 0: return
    forward(s)
    tree(d - 1, s * .8)
    right(120)
    tree(d - 3, s * .5)
    right(120)
    tree(d - 3, s * .5)
    right(120)
    backward(s)


tree(15, n)
backward(n / 2)

for i in range(200):
    a = 200 - 400 * random.random()
    b = 10 - 20 * random.random()
    up()
    forward(b)
    left(90)
    forward(a)
    down()
    if random.randint(0, 1) == 0:
        color('tomato')
    else:
        color('wheat')
    circle(2)
    up()
    backward(a)
    right(90)
    backward(b)
time.sleep(60)

我看你抄的代码里这里错了：